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Tatiana [17]
3 years ago
6

the question says, for exercises a-d decide whether the statement is correct or incorrect. Explain your reasoning in words or by

drawing a picture. Please help :(

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:


Step-by-step explanation:

Take a. for example. Use the largest denominator and divide it by the smaller one, in this case 12 and 3. So 12/3=4. Multiple your product with the denominator. 4 x 1 = 4. Therefore 1/3 = 4/12.

Use that method for all of the questions. I hope you understand. Good luck :) !!  

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What does1/3 of 5 equal?
svetoff [14.1K]

Answer:

1.666666666666667

Step-by-step explanation:

5/3

= 1.666666666666667

5 0
3 years ago
Read 2 more answers
Help with math please
MakcuM [25]

Answer:

You are correct,y = 0.

Step-by-step explanation:

y = 4 x -3 + 12

y = -12 + 12

y = 0

Hope that helps!

4 0
3 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
16. Solve for C: 6c - 1 - 4c = -49
lesantik [10]

Answer:

c = -24

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

<u />

Step-by-step explanation:

<u>Step 1: Define</u>

6c - 1 - 4c = -49

<u>Step 2: Solve for </u><em><u>c</u></em>

  1. Combine like terms:                     2c - 1 = -49
  2. Isolate <em>c</em> term:                               2c = -48
  3. Isolate <em>c</em>:                                        c = -24
7 0
3 years ago
A researcher conducts an experiment comparing two treatment conditions with 20 scores in each treatment condition.
Savatey [412]
To determine the number of subjects that are needed for the experiments, we multiply the number of independent variables with the number of scores. For example, there are n independent variables then, there are approximately,

                                number of subjects = 20 x n = 20n
6 0
3 years ago
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