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Rina8888 [55]
3 years ago
10

Rewrite the function f(x)=7 (1/2)^3x using the properties of exponents.

Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

f(x) = (7 x)\/8

Step-by-step explanation:

idk, i just used wolframalpha mate...

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The area of inner total surface of acubical water tank is 54m². How m3 many of water does it hold?​
klio [65]

Answer:

0

Step-by-step explanation:

54m² - 54m² = 0

Water is 0

6 0
2 years ago
Evaluate the following expression. 8to the power of 3 − 9 ⋅ 2 ÷ 3 = ?
ahrayia [7]

Answer:

8^-3  I think  (i'm too lazy to simplify)

Step-by-step explanation:

3 - 9 * 2 ÷ 3 = ?

3 - 18 ÷ 3 = ?

3 - 6 = -3

8 to the power of -3

hmmmm i dont think im right tell me if im not

3 0
3 years ago
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 83 type K batteries and a sample of 77
agasfer [191]

Answer:

1. Null Hypothesis, H_0 : \mu_1 = \mu_2  {mean voltage for these two types of

                                                         batteries is same}

Alternate Hypothesis, H_1 : \mu_1\neq \mu_2 {mean voltage for these two types of

                                                            batteries is different]

2. Test Statistics value = -5.06

4. Decision for the hypothesis test is that we will reject null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, \mu_1 = true mean voltage for type K batteries.

            \mu_2 = true mean voltage for type Q batteries.

So, <em>Null Hypothesis, </em>H_0<em> : </em>\mu_1 = \mu_2<em>  {mean voltage for these two types of </em>

<em>                                                          batteries is same}</em>

<em>Alternate Hypothesis, </em>H_1<em> : </em>\mu_1\neq \mu_2<em> {mean voltage for these two types of </em>

<em>                                                             batteries is different]</em>

The test statistics we use here will be :

                          \frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }   follows t_n__1+n_2-2

where, X_1bar = 9.29         and      X_2bar =  9.65

                s_1    = 0.374       and             s_2 =  0.518

                 n_1   = 83            and             n_2  =  77

                  s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } =   \sqrt{\frac{(83-1)0.374^{2}+(77-1)0.518^{2}  }{83+77-2} } = 0.45                                                   Here, we use t test statistics because we know nothing about population standard deviations.

      Test statistics = \frac{(9.29-9.65) - 0 }{0.45\sqrt{\frac{1}{83}+\frac{1}{77}  } }  follows t_1_5_8

                              = -5.06

<em>At 0.05 or 5% level of significance t table gives a critical value between (-1.98,-1.96) to (1.98,1.96) at 158 degree of freedom. Since our test statistics is less than the critical table value of t as -5.06 < (-1.98,-1.96) so we have sufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that mean voltage for these two types of batteries is different.

7 0
4 years ago
PLEASE HELP ME WITH THIS 17 points!! PLEASEEEE IM BEGGING YOU!!!
slega [8]

Answer:

x = 2

Step-by-step explanation:

Step 1: Convert to math

5x + 1 = 3x + 5

Step 2: Solve for <em>x</em>

  1. Subtract 4x on both sides: 2x + 1 = 5
  2. Subtract 1 on both sides: 2x = 4
  3. Divide both sides by 2: x = 2

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

5(2) + 1 = 3(2) + 5

10 + 1 = 6 + 5

11 = 11

7 0
3 years ago
Read 2 more answers
Simplify 27 to the negative 2 thirds power.
Tatiana [17]
27^(-2/3)=1/((∛27)^2)

=1/3^2

=1/9
5 0
4 years ago
Read 2 more answers
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