Three random question!
2 answers:
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Answer:
A)
B)
C)
Step-by-step explanation:
We are given the function:
A)
Given that h(1) = 20, we want to find <em>k</em>.
h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:
Simplify:
Anything raised to zero (except for zero) is one. Therefore:
B)
Given that h(1) = 40, we want to find 2<em>k</em> + 1.
Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:
Simplify:
We can take the natural log of both sides:
By definition, ln(e) = 1. Hence:
Therefore:
C)
Given that h(1) = 10, we want to find <em>k</em> - 3.
Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:
Simplfy:
Take the natural log of both sides:
Therefore:
Therefore:
Answer:
\frac{1}{230230}
Step-by-step explanation:
Given that in a certain lottery, an urn contains balls numbered 1 to 26
From this urn, 6 balls are chosen randomly, without replacement.
Bet amount 1 dollar and he selects a set of six numbers.
If these match with those chosen from the urn he wins (order does not matter)
Total ways of choosing 6 out of 26 =
The way he selects = 1
Hence probability of winning =
with one ticket