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Svetlanka [38]
3 years ago
10

Evaluate each expression, m= 4, x= 9, and r= 1/6

Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0
4. 14
5. 6
6. 1/12
These are the answers to the questions

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Roberta Arthur had the following reciepts for the week of April 12th: 50$ gift; 25$ rebate; April 13th, 2.45$ refund on aluminum
oksian1 [2.3K]

Answer:

$329.44

Step-by-step explanation:

 $50-25= 25

 25.00-2.45=22.55

 299.89+22.55=322.44

322.44+7.00= 329.44

I didnt see april 15 if its supposed to be added i there just add 299.89 to the total.

7 0
3 years ago
WILL MARK YOU BRAINLIEST, PLEASE HELP!!!
lutik1710 [3]

Given:ABCD is a rhombus.

To prove:DE congruent to BE.

In rombus, we know opposite angle are equal.

so, angle DCB = angle BAD

SINCE, ANGLE DCB= BAD

SO, In triangle DCA

angle DCA=angle DAC

similarly, In triangle ABC

angle BAC=angle BCA

since angle BCD=angle BAD

Therefore, angle DAC =angle CAB

so, opposite sides of equal angle are always equal.

so,sides DC=BC

Now, In triangle DEC and in triangle BEC

1. .DC=BC (from above)............(S)

2ANGLE CED=ANGLE CEB (DC=BC)....(A)

3.CE=CE (common sides)(S)

Therefore,DE is congruent to BE (from S.A.S axiom)

7 0
2 years ago
Sam runs for 10 minutes The graph shows his puse, in beats per minute. 100- (beats per min) 80- 1 2 3 5 6 7 8 9 10 Time (min) By
Inessa05 [86]

The rate at which his pulse is increasing after 3 minutes is 9.5 beats per minute

<h3>How to determine the beat rate after 3 minutes?</h3>

The given graph shows the curve and the tangent.

From tangent line, we have the following points:

(x,y) = (3,119) and (1,100)

The beat rate (m) at this point is:

m = \frac{y_2 -y_1}{x_2 -x_1}

So, we have:

m = \frac{100 - 119}{1 - 3}

Evaluate the differences

m = \frac{-19}{-2}

Evaluate the quotient

m = 9.5

Hence, the rate at which Sam's pulse is increasing after 3 minutes is 9.5 beats per minute

Read more about rates of tangent lines at:

brainly.com/question/6617153

#SPJ1

5 0
2 years ago
For selected years, the national health care expenditure, in billion of dollors can be modelled by H=29.57e^0.0970t, remains acu
Sliva [168]

Answer:

The correct answer is 54.76 years.

Step-by-step explanation:

The national health care expenditure (H) , in billion of dollars is modeled by

H = 29.57 × e^{0.0970t}.

To measure the time before which national health expenditure reach 6000 billion dollars.

Thus putting the value of H = 6000 in the above modeled equation we get,

⇒ 6000 = 29.57 × e^{0.0970t}

⇒ \frac{6000}{29.57} = e^{0.0970t}

⇒ 202.908 = e^{0.0970t}

Taking logarithm with the base of e (㏑) both sides we get,

⇒ ㏑ 202.908 = ㏑ e^{0.0970t}

⇒ ㏑ 202.908 = 0.0970 × t

⇒ 0.0970 × t = 5.312

⇒ t = \frac{5.312}{0.0970}

⇒ t = 54.76.

Thus the total time required before which national health expenditure reach 6000 billion dollars is 54.76 years.

3 0
3 years ago
A random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph. From past information, it is kn
loris [4]

Answer:

95 percent confidence interval for μ is determined by

(60.688 ,  69.312)

a) be the same

Step-by-step explanation:

<u>Step (i)</u>:-

Given data a random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph.

The sample size is n= 121

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

<u>Step (ii) :</u>-

Given  The 95 percent confidence interval for μ is determined as

(61.08, 68.92)

we are to reduce the sample size to 100 (other factors remain unchanged) so

given The sample size is n= 100

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

<u>Step (iii)</u>:-

95 percent confidence interval for μ is determined by

(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96 \frac{S.D}{\sqrt{n} } )

(65 - 1.96\frac{22}{\sqrt{100} } , 65 + 1.96 \frac{22}{\sqrt{100} } )

(65 - 4.312 ,65 +4.312)

(60.688 ,  69.312) ≅(61 ,69)

This is similar to (61.08, 68.92) ≅(61 ,69)

<u>Conclusion</u>:-

it become same as (61.08, 68.92)

4 0
3 years ago
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