Well, the first thing you would do is find like denominators for each fraction.
Since the smallest common term between the two is 40, that will be your denominator for each. Then you would multiply the numerator by the number your denominator was multiplied to get to 40. So, you would end up with 16/40 because 5*8=40 and 2*8=16 and 5/40 because 8*5=40 and 1*5=5.
After that, you would just subtract them.
16/40 - 5/40 = 11/40 and as a decimal that is 0.275. So, Joe has eaten 0.275 more pizza than Jane.
Hope this helps! :)
Answer:
4
Step-by-step explanation:
if 36.24 is divided by 90.6 can be 9.06
36.24÷9.06
4
or by other style
36.24×100=3624
90.6×100= 9060
according to the question
36.24÷90.6 or 3624÷9060
=4 or 0.4
From trigonometry we know that:
if 
then,
(where
is an integer)
This can be rewritten in degrees as:
.............(Equation 1)
Now, in our case, 
Therefore, (Equation 1) can be written as:
..........(Equation 2)
Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of
that match.
For n=2, (Equation 2) gives us:
.
Thus, 
Now, we know that: 
Let n=-1, then:

Thus, 
Likewise, 
Only the last option
will never match
because no integral value of
will ever give 
Thus the last option is the correct option.
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Well, the answer would bee 1/10 for a simple reason: the 3 in 7.315 is in the tenth's spot while the 3 in 893.5 is in the ones. a one spot different that can be proven with logic.