Answer:
Length of rectangle = 16 cm
Width of rectangle = 4 cm
Step-by-step explanation:
Given:
Area of rectangle = 64 cm²
Find:
Length and width
Computation:
Assume;
Length of rectangle = a
So,
Width of rectangle = a -12
Area of rectangle = l x b
So,
a(a-12) = 64
a² - 12a - 64 = 0
a² - (16-4)a - 64 = 0
a² - 16a+ 4a - 64 = 0
a (a-16) + 4(a-16)= 0
(a-16)(a+4) = 0
a= 16 , a = -4
So,
Length of rectangle = 16 cm
Width of rectangle = a -12
Width of rectangle = 16 -12
Width of rectangle = 4 cm
Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
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