The solution to this system of linear equations would be (0,2), since you look at the point of intersection. Where the two lines intersect, you look at the corresponding x and y values. Hence, the solution is (0,2). I hope you understand.
Thank you,
kaloliavivek
Answer: The system of equations is
40x + 55y = 920
40x + 65y = 1000
x is the cost of the adult ticket; y is the cost of the child ticket
Step-by-step explanation:
If you have to solve this, elimination is a good method.
Subtract the top equation from the second equation.
40x + 65y = 1000
<u>-40x + 55y = 920 </u> x cancels Solve for y
0 + 10y = 80 Divide both sides by 10
y = 8 . Substitute 8 for y in either equation and solve for x
40x + 65(8) = 1000
40x + 520 = 1000 Subtract 520 from both sides
40x = 1000 - 520
40x = 480 Divide both sides by 40
x = 12
1. f(x) = 9x² + 6x - 8
f(x) = (3x - 2)(3x + 4)
When (3x - 2) = 0, then x = 2/3
When (3x + 4) = 0, then x = -4/3
Answer: The zeros are two divided by three and negative four divided by three.
2. f(x) = 9x³ - 45x² + 36x
f(x) = 9x(x² - 5x + 4)
= 9x(x - 1)(x - 4)
When 9x = 0, then x = 0
When (x-1) = 0, then x = 1
When (x-4) = 0, then x = 4
Answer: 0, 1 and 4
3. f(x) = 4(x+7)²(x-7)³
When (x+7)² = 0, then x = -7 (twice)
When (x-7)³ = 0, then x = 7 (thrice)
Answer: 7, multiplicity 2; -7 multiplicity 3
4. The zeros of f(x) are √5, -√5, -7
The factors of f(x) are (x-√5)(x+√5)(x+7)
Note that (x-√5)(x+√5) = x² - (√5)² = x² - 5
f(x) = (x²-5)(x+7)
= x³ + 7x² - 5x - 35
Answer: f(x) = x³ + 7x² - 5x - 35
5. Expand (2x + 4)³
From Pascal's Triangle, the coefficients are 1 3 3 1
Therefore
(2x + 4)³ = 1(2x)³(4)⁰ + 3(2x)²(4)¹ + 3(2x)¹(4)² + 1(2x)⁰(4)³
= 8x³ + 48x² + 96x + 64
Answer: 8x³ + 48x² + 96x + 64
Answer:
0.25
Step-by-step explanation:
As a decimal, 0.25
As a fraction, 1/4
As a percentage, 25%
Answer:
178.98 ft2
Step-by-step explanation:
we know that
The area of the circular path alone is equal to subtract the area of the circular garden from the area of the complete circle (circular garden plus circular path)
so
where
---> radius of circular garden
----> radius of the circular garden plus radius circular path
substitute
