A circular garden with a radius of 8 feet is surrounded by a circular path with a width of 3 feet.
2 answers:
Answer:
178.98 ft2
Step-by-step explanation:
we know that
The area of the circular path alone is equal to subtract the area of the circular garden from the area of the complete circle (circular garden plus circular path)
so
where
---> radius of circular garden
----> radius of the circular garden plus radius circular path
substitute
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Answer:
1. Perpendicular
2. Isosceles
3. Never
Step-by-step explanation:
1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.
2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )
In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )
But, OA = OC because both are radius of same circle
So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC
⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.
3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius
