A circular garden with a radius of 8 feet is surrounded by a circular path with a width of 3 feet.

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

B. 178.98 ft2

Step-by-step explanation:

Vladimir [108]3 years ago

5 0

Answer:

178.98 ft2

Step-by-step explanation:

we know that

The area of the circular path alone is equal to subtract the area of the circular garden from the area of the complete circle (circular garden plus circular path)

$A=\pi (r_2^2-r_1^2)$

where

$r_1=8\ ft$ ---> radius of circular garden

$r_2=8+3=11\ ft$ ----> radius of the circular garden plus radius circular path

substitute

$A=3.14 (11^2-8^2)=178.98\ ft^2$

You might be interested in

a listing for a home for sale is shown as follows: “3/2/1 house for sale. price 140000” what does “3/2/1” mean

Inessa05 [86]

Answer:

Step-by-step explanation:

Usually when purchasing a house you refer to the bedroom then the bathroom then potentially your garden width/height or you garage

5 0

3 years ago

A recipe for a fruit drink calls for 2 cups of fruit juice for every 5 cups of water. Look at each drink mix. Does each drink mi

stealth61 [152]

1. Yes
2. No
3. Yes
4.no

4 0

3 years ago

Read 2 more answers

Please help!! 15 points!!

vampirchik [111]

$- 1 = - 3 - 4 \cos(4θ + \frac{2\pi}{3} ) \\ - 1 + 4 \cos(4θ + \frac{2\pi}{3} ) = - 3 \\ 4 \cos(4θ + \frac{2\pi}{3} ) = - 3 + 1 \\ 4 \cos(4θ + \frac{2\pi}{3} ) = - 2 \\ \cos(4θ + \frac{2\pi}{3} ) = - \frac{1}{2} \\ \cos(4θ + \frac{2\pi}{3} ) = - \frac{1}{2} \\ \cos(2\pi - (4θ + \frac{2\pi}{3} )) = - \frac{1}{2} \\ 4θ + \frac{2\pi}{3} = arccos( - \frac{1}{2} ) \\ \cos( \frac{4\pi}{3} - 4θ) = - \frac{1}{2}$