Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
what is the best and easiest method to use to find sides A and B?
B
The answer is: ALWAYS TRUE .
_________________________________________
Odd integers are 2 apart
they are n, n+2, n+4
the sum is 75
n+n+2+n+4=75
3n+6=75
minus 6 both sides
3n=69
divide both sides by 3
n=23
n+2=25
n+4=27
the integers are 23,25,27
It would be 1,800 because when you round 34 it becomes 30 and when you round 57 becomes 60 and 30 x 60 = 1,800. This helps me round remember "4 or less let it rest, 5 or more raise the score" hope that makes rounding easier!!
