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elixir [45]
4 years ago
5

write an equation in slope-intercept form of the line whose y-intercept is -3 and the line is perpendicular line whose equation

is 3x-2y=9 what is the slope intercept form?
Mathematics
1 answer:
Artemon [7]4 years ago
8 0

first you need to find the slope of he current equation by changing it to y=mx+b

3x-2y=9  subtract 3x from both sides

-2y=-3x+9  divide both sides by -2

y+3/2x-9/2  Your slope of the existing is 3/2 or 1 1/2

a perpendicular line has the opposite reciprocal slope so 3/2 would be -2/3

-3 is your y intercept. now you can make your equation

y=-2/3x-3

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Answer:

Multiply the second equation by -3 to get -3x - 9y = -30.

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When eliminating, you need to find a term with the negative of that term to combine so that they cancel each other out. An example would be 3x in the first equation and (-3x) in another equation so that when added, it becomes: 3x-3x = 0.

In the second equation, you see that there is already an x there and you just need to make it become (-3x). Thus, you multiply the entire second equation by -3 to make -3x. Once you have done that, you can combine the two equations and eliminate 3x from the first equation.

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