Question

What is the distance in units between the points (8,-1) and (-2,-1) on a coordinate plane?

Answer 1

You can use the distance formula.
The distance formula says the distance between two given points (x1, y1) and (x2, y2)
= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

Your given points are (8, -1) and (-2, -1).
The distance will be
$\sqrt{(-1+1)^2+(-2-8)^2} \\ = \sqrt{100} \\ =10$.

But you could have recognized that both points have the same y-coordinate of -1, which means change in distance is determined by change in x-coordinates only.
Change in x-coordinates is |-8 - 2| = 10. There is absolute value because distance cannot be negative.