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erica [24]
3 years ago
8

What is the distance in units between the points (8,-1) and (-2,-1) on a coordinate plane?

Mathematics
1 answer:
Sliva [168]3 years ago
3 0
You can use the distance formula.
The distance formula says the distance between two given points (x1, y1) and (x2, y2)
= \sqrt{(x2-x1)^2+(y2-y1)^2}

Your given points are (8, -1) and (-2, -1).
The distance will be
\sqrt{(-1+1)^2+(-2-8)^2}  \\ =  \sqrt{100}  \\ =10.

But you could have recognized that both points have the same y-coordinate of -1, which means change in distance is determined by change in x-coordinates only.
Change in x-coordinates is |-8 - 2| = 10. There is absolute value because distance cannot be negative.
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A(5 1) b(1 5) and c(-3 -1) are the vertices of triangle abc. find the LENGTH of median ad
faltersainse [42]

Answer:

\text{Length of median AD}=\sqrt{37}

Step-by-step explanation:

We are given the vertices of triangle ABC. We need to find the length of median AD.

Please see the attachment for figure.

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Using the formula of mid point. we get coodrinate of D

\text{Mid Point :}\left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right )

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AD is median of triangle ABC. Now we find length of median AD using distance formula of two coordinate.

\text{Distance }=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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AD=\sqrt{(5+1)^2+(1-2)^2}\Rightarrow \sqrt{36+1}

\text{Length of median AD}=\sqrt{37}

Thus, \text{Length of median AD}=\sqrt{37}

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3 years ago
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2 years ago
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