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4 years ago

Which of the following sequences represents an arithmetic sequence?

Mathematics

1 answer:

dalvyx [7]4 years ago

7 0

Answer:

Step-by-step explanation:

-5+2,-3+2,-1+2,1

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Can someone do 11,13,14,15?

Juliette [100K]

Theres no linked picture.

4 0

3 years ago

The perimeter of the base of the prism is __ units.

swat32

The bases of the prism are the triangular faces.

One side is marked 3 units. The vertical sides to the left of the triangles are 4 units. In a right triangle, if the legs measure 3 and 4, the hypotenuse measures 5.

The three sides of the triangular base measure 3, 4, and 5.

Perimeter = sum of the lengths of the sides

Perimeter = 3 + 4 + 5 = 12

Answer: 12 units

7 0

3 years ago

A right cone has a radius of 13 cm and a slant height of 20 cm. Find its surface area.

devlian [24]

Answer:

$A=1347.7\ cm^2$

Step-by-step explanation:

Given that,

Radius of a cone, r = 13 cm

Slant height of the cone, l = 20 cm

We need to find the surface area of the cone. The formula for the surface area of the cone is given by :

$A=\pi rl +\pi r^2$

Put all the values,

$A=\pi r(l + r)\\\\A=\pi \times 13(20 + 13)\\\\A=1347.7\ cm^2$

So, the surface area of the cone is $1347.7\ cm^2$ .

5 0

3 years ago

Solve (tan^2 x)/2 -2cos^2 x =1 for 0 <= x <= 2pi

Neko [114]

Answer:

sorry don’t understand it’s all close together

Step-by-step explanation:

4 0

3 years ago

Whats the domain for this equation?

fgiga [73]

Strictly speaking an equation does not have a domain. A function does. Though it may make sense to speak about a solution set to this equation over a domain.

The following could be helpful towards an answer: The equation has two sides. The left hand side is a non-linear function and the right hand side is a line with slope -1 and y-intercept of 1.

The function $\log_5(6-5^x)$ has a domain over all Reals x for which it holds $6-5^x > 0 \\6 > 5^x\\\log_5 6 > x$ so the domain of the nonlinear function is $-\infty$ .

The domain of the linear function 1-x is all Reals: $-\infty$

So, together you could say the equation's solutions are defined over the domain $-\infty$ .

Lmk if you have questions.

7 0

3 years ago