Answer: See below
Step-by-step explanation:
<u>Question 3:</u>
<u>Challenge:</u>
![\begin{aligned}&x(s)=s \quad ,s \in[0,4] \\&y(s)=\left\{\begin{array}{cc}3 s & , s \in[0,1] \\5-2 s &, s \in[1,2] \\1 & s \in[2,4]\end{array}\right.\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26x%28s%29%3Ds%20%5Cquad%20%2Cs%20%5Cin%5B0%2C4%5D%20%5C%5C%26y%28s%29%3D%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bcc%7D3%20s%20%26%20%2C%20s%20%5Cin%5B0%2C1%5D%20%5C%5C5-2%20s%20%26%2C%20s%20%5Cin%5B1%2C2%5D%20%5C%5C1%20%26%20s%20%5Cin%5B2%2C4%5D%5Cend%7Barray%7D%5Cright.%5Cend%7Baligned%7D)
Solution-
Circumference of circle: 14 pi feet or 43.98.
But here answer is option A.
Answer:A
Step-by-step explanation:
LHS= 1 + cot^2A/1+cosecA
=(1+cosecA + cot^2A)/1+cosecA
{By using basic trigonometric theorem cot^2A = cosec^2A - 1}
=(1+cosecA + cosec^2A - 1)/(1+cosecA)
=(cosecA + cosec^2A)/(1+cosecA)
=[cosecA (1+cosecA)]/(1+cosecA)
{Cancelling 1+cosecA}
=cosecA
No.
0.3^4 or 0.3x0.3x0.3x0.3= 0.0081
0.9^2 or 0.9x0.9=0.81
These are not equivalent.
