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3 years ago

List all compsite numbers between 41-50

Mathematics

1 answer:

crimeas [40]3 years ago

8 0

43, 47, is the composite numbers between 41 and 50

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Apply Newton’s method to estimate the solution of x3 − x − 1 = 0 by taking x1 = 1 and finding the least n such that xn and xn +

ss7ja [257]

Solution :

Given

$f(x)=x^3-x-1, x_1=1$

$f'(x)=3x^2-1$

Let the initial approximation is $x_1 =1$

So by Newton's method, we get

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)},n=1,2,...$

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}=1-\frac{1^3-1-1}{3(1)^2-1}=1.5$

$x_3=1.5-\frac{(1.5)^3-1.5-1}{3(1.5)^2-1}=1.34782608$

$x_4=1.34782608-\frac{(1.34782608)^3-1.34782608-1}{3(1.34782608)^2-1}=1.32520039$

$x_5=1.32520039-\frac{(1.32520039)^3-1.32520039-1}{3(1.32520039)^2-1}=1.32471817$

$x_6=1.32471817-\frac{(1.32471817)^3-1.32471817-1}{3(1.32471817)^2-1}=1.32471795$

$x_5 \approx x_6$ are identical up to eight decimal places.

The approximate real root is x ≈ 1.32471795

∴ x = 1.32471795

4 0

3 years ago

-3/4x>12 solve for x

Ad libitum [116K]

Answer:

$\Huge\boxed{\mathsf{\rightarrow X$

Step-by-step explanation:

$\Large\boxed{\mathsf{SUBJECT: MATH}}$

Isolate x on one side of the equation.

Find the value of x.

First, multiply -1 from both sides.

(-3/4x)(-1)<12(-1)

Solve.

12(-1)=-12

3/4x<-12

Next, multiply 4 from both sides.

4*3/4x<4(-12)

Solve.

Multiply the numbers from left to right.

4(-12)=-48

3x<-48

Then, divide by 3 from both sides.

3x/3<-48/3

Solve.

Divide the numbers from left to right.

-48/3=-16

X<-16

$\Large\boxed{\Rightarrow \mathsf{X$

The correct answer is x<-16.

6 0

3 years ago

How many lines of symmetry does this figure have?

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

There are two lines of symmetry and here I list them:

1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).

2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.

A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.

So, we only have 2 symmetry lines.

4 0

3 years ago

Helppp please reallly fasttt!!!

Bingel [31]

Answer:

Step-by-step explanation:

$3^{2}+ 7^{2} = EF^{2}$