The solution for the problem is:
I will first get the first five terms so that I could easily locate the third term of this problem:So, substituting the values:
T(1) = 1^2 = 1T(2) = 2^2 = 4T(3) = 3^2 = 9T(4) = 4^2 = 16T(5) = 5^2 =25
So the third terms is T(3) = 3^2 = 9
The scale faction is 20 to 1 hope that helps
An arithmetic sequence has a common difference.
143 - 130 = 13
156 - 143 = 13
169 - 156 = 13
The common difference is 13.
a1 = 130
a2 = 130 + 13
a3 = 130 + 2 * 13
a4 = 130 + 3 * 13
...
an = 130 + (n - 1) * 13
an = 130 + 13(n - 1)
an = 130 + 13n - 13
an = 117 + 13n
an = 13n + 117
<em>Answer is x + 12</em>
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<h2>
Explanation:</h2>
Hello! Recall that you have to write clear questions in order to get exact answers. So I'll help you assuming that the two expressions are the following:
First expression:
Second expression:
So the operation we need to perform is:
Recall some rules:
Hence:
<h2>Learn more:</h2>
Simplify: brainly.com/question/1291365
#LearnWithBrainly
1/2 + 3/x = 3/4
3/x = 3/4 - 1/2
3/x = 3/4 - 2/4
3/x = 1/4....this is a proportion, so we cross multiply
(1)(x) = (3)(4)
x = 12
check..
1/2 + 3/12 = 3/4
6/12 + 3/12 = 3/4
9/12 = 3/4
3/4 = 3/4 (correct)
so x = 12
