Answer: something
Step-by-step explanation:
Cant see the attatchment
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:
24 = ab^2
48 = ab^3
divide equation 2 by equation 1:
2 = b^1
or, more simply:
2 = b
now plug b into one of the equations to get "a":
24 = a*2^2
24 = a*4
6 = a
So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
Answer:
the answer is 9×9 and -9×-9
Cross Multiply by 'x - 5'
Hence
y(x - 5) = 4 -3x
xy - 5y = 4 - 3x
Move all the terms containing an 'x' to one side of the equals and all the others to the opposite side.
xy + 3x = 4 + 5y
Factor out 'x'
x(y + 3) = 4 + 5y
'Cross' divide by 'y + 3'
x = ( 4 + 5y) / (y + 3 )
'x' is now the subject.
Answer:
Step-by-step explanation:
Let the number of dimes be d and quarters be q
<u>The value is $8.80 = 880¢, so:</u>
- 10d + 25q = 880 ⇒ 2d + 5q = 176
<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>
- 25d + 10q = 730 ⇒ 5d + 2q = 146
<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>
- 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
- 4d - 25d = -378
- -21d = -378
- d = -378/-21
- d = 18