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Anettt [7]
4 years ago
15

What is the equation of f(x)?

Mathematics
2 answers:
leva [86]4 years ago
3 0

Answer: A-16b8

Step-by-step explanation:

JulijaS [17]4 years ago
3 0

Answer:

The answer is  B, -8(4x)

Step-by-step explanation:

Just took the test :)

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"If &lt; A and then m&lt; A + m/B = 90°"<br> A. Complement Theorem<br> B. Definition of a Right Angle<br> C. Congruent Complemen
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If < A and then m< A + m/B = 90°, then D. Definition of Complementary Angles

<h3>What is a complementary angle?</h3>

When the sum of two angles is 90°, the angles are said to be complementary. In other words, if two angles add up to form a right angle, they are called complementary angles. The two angles are said to complement each other in this context.

Supplementary angles are two angles that add up to 180 degrees, whereas complementary angles are two angles that add up to 90 degrees.

An angle measuring 72 degrees has a complement of 18 degrees.

Therefore, based on the information given, the correct option is D.

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8 0
1 year ago
Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
3 years ago
A newspaper prints that the average square footage of a house in Cleveland is significantly less than 2,379 square feet.
tatyana61 [14]

Answer: i’m confused on what the question is

Step-by-step explanation:

6 0
3 years ago
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