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sergejj [24]
3 years ago
10

One pound of red grapes cost $2.42 Ella buys worth 0.5 pound how much does she spend on red grapes

Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:

1.21

Step-by-step explanation:

The cost of the grapes is the price per pound times the number of pounds

cost = 2.42 * .5

cost = 1.21

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Mrs. Miller has a rectangular garden with a length of 20 feet long with an area of (20x-200) square feet. Write an expression th
krek1111 [17]

Perimeter = (20 + 2x) mm.

Step-by-step explanation:

The octopus pupil has length 20 mm and the expression for its area is given by (20x - 200) square mm.

If the width of the octopus pupil is w, then 20w = 20x - 200

⇒ w = (x - 10) mm.

Therefore, the expression for its perimeter is 2(Length + Width) = 2 ( 20 + x - 10) = 2( 10 + x) = (20 + 2x) mm. (Answer)

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3 years ago
What is y+1=5/6(x-2) in standard form?
vfiekz [6]
The standard form is 5x-6y=16
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3 years ago
5. There are two kinds of products (called DA and GA) produced in your company every day. Alsothere are two kinds of materials (
chubhunter [2.5K]

Answer:

  • a) $56000
  • b) DA = 2, GA = 10

Step-by-step explanation:

<u>Given</u>

  • DA = A + B ⇒ $3000
  • GA = A + 2B ⇒ $5000
  • Number of A = 12
  • Number of B = 22

<u>We can see from the equations that</u>

  • GA - DA = B ⇒ $2000 and
  • A = $1000 and B = $2000 in terms of profit

<u>So greater use of unit B brings greater profit. We don't want any unit is left over, so get this equation.</u>

  • A + B = 12
  • A + 2B = 22

Is the equation set to indicate use of the units A and B

<u>Solving we get </u>

  • A = 2 and
  • B = 10

<u>It this case all the units are used and profit is maximum</u>

  • 2*$3000 + 10*$5000 = $56000
  • Number of DA = 2
  • Number of GA = 10
8 0
3 years ago
A pool table is 8 feet long and 4 feet wide. How far is it from one corner pocket to the diagonally opposite corner pocket?
Mashutka [201]

Answer: 8.94427

Step-by-step explanation: using the Pythagorean theorem which is A squared plus B squared equals C squared you can find this

3 0
3 years ago
a. 0.98 – 0.053 b. 0.67 – 0.4 c. 0.3 – 0.002 d. 3.2 – .789 e. 6.53 – 4.298 f. 6 – 4.32 g. 7 – 3.574 h. 4.83 – 1.8 i. 3.7 – 1.8 j
Pavlova-9 [17]

a. 0.927

We have:

0.98 – 0.053

We can re-write it as:

0. 9 8 0 -

0. 0 5 3

Moving digits to the right:

0. 9 7 10 -

0. 0 5 3

Digit-per-digit subtraction:

0. 9 2 7


b. 0.27

We have:

0.67 – 0.4

We can re-write it as:

0. 6 7 -

0. 4 0

Digit-per-digit subtraction:

0. 2 7


c. 0.298

We have:

0.3 – 0.002

We can re-write it as:

0. 3 0 0 -

0. 0 0 2

Moving digits to the right:

0. 2 10 0 -

0. 0 0 2

Again:

0. 2 9 10 -

0. 0 0 2

Digit-per-digit subtraction:

0. 2 9 8


d. 2.411

We have:

3.2 – .789

We can re-write it as:

3. 2 0 0 -

0. 7 8 9

We need to rewrite the first term by moving digits to the right several times:

3. 2 0 0 = 2. 12 0 0 = 2. 11 10 0 = 2. 11 9 10

So now we have:

2. 11 9 10 -

0. 7 8 9

Digit-per-digit subtraction:

2. 4 1 1


e. 2.232

We have:

6.53 – 4.298

We can re-write it as:

6. 5 3 0 -

4. 2 9 8

We need to rewrite the first term by moving digits to the right several times:

6. 5 3 0 = 6. 5 2 10 = 6. 4 12 10

So now we have:

6. 4 12 10 -

4. 2 9 8

Digit-per-digit subtraction:

2. 2 3 2


f. 1.68

We have:

6 – 4.32

We can re-write it as:

6. 0 0 -

4. 3 2

We need to rewrite the first term by moving digits to the right several times:

6. 0 0 = 5. 10 0 = 5. 9 10

So now we have:

5. 9 10 -

4. 3 2

Digit-per-digit subtraction:

1. 6 8


g. 4.426

We have:

7 – 3.574

We can re-write it as:

7. 0 0 0 -

3. 5 7 4

We need to rewrite the first term by moving digits to the right several times:

7. 0 0 0 = 6. 10 0 0 = 6. 9 10 0 = 6. 9 9 10

So now we have:

6. 9 9 10 -

3. 5 7 4 =

Digit-per-digit subtraction:

3. 4 2 6


h. 3.03

We have:

4.83 – 1.8

We can re-write it as:

4. 8 3 -

1. 8 0

We can immediately do the digit-per-digit subtraction:

3. 0 3


i. 2.9

We have:

3.7 – 1.8

We can re-write it as:

3. 7 -

1. 8

We need to rewrite the first term by moving digits to the right:

3. 7 = 2. 17

So now we have:

2. 17 -

1. 8 =

Digit-per-digit subtraction:

2. 9


j. 4.538

We have:

16.17 – 11.632

We can re-write it as:

1 6 . 1 7 0 -

1 1 . 6 3 2

We need to rewrite the first term by moving digits to the right:

1 6. 1 7 0 = 1 6. 1 6 10 = 1 5. 11 6 10  

So now we have:

1 5. 11 6 10 -

1 1. 6 3 2 =

Digit-per-digit subtraction:

0 4. 5 3 8

3 0
3 years ago
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