1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
3 years ago
6

What is the solution oflog6x + log6(x + 5) = 2?

Mathematics
2 answers:
DedPeter [7]3 years ago
7 0

Answer:

The answer is 4 on edg

Step-by-step explanation:

I just answered it :)

exis [7]3 years ago
4 0

Answer:

Doesn't have solution.

Step-by-step explanation:

x ≠ 0; x > 0 (I)

x - 5 > 0

x > 5 (II)

log_6 x + log_6 (x + 5) = 2 \\\ log_6 [x(x + 5)] = 2 \\\ x^2 + 5x = 36 \\\ x^2 + 5x - 36 = 0 \\\ \Delta = 5^2 - 4.1.(- 36) \\\ \Delta = 169 \\\ \sqrt{\Delta} = \pm 13 \\\ x' = \frac{- 5 + 13}{2} \\\\ x' = 4 \\\ x" = \frac{- 5 - 13}{2} \\\\ x" = - 9

Then, this expression doesn't have solution.

I Hope I've helped you.

You might be interested in
What are the subjects colors? like is math red??
3241004551 [841]

Step-by-step explanation:

Blue is for physics........

3 0
2 years ago
Please help i need answer asap
ycow [4]

Answer:

1: x=-3

2: x=1 is the answer

5 0
2 years ago
The intersection of a plane and a line segment can be a point true or false
77julia77 [94]

Answer:

true

Step-by-step explanation:

add

4 0
2 years ago
Which graph represents the function?<br><br> f(x)=2x√+1
gogolik [260]

Answer:

the 3rd one

Step-by-step explanation:

I just think

4 0
2 years ago
F(x)=X over x^3-2x^2+5x why will this have no zeros​
Mumz [18]

If you evaluate directly this function at x=0, you'll see that you have a zero denominator.

Nevertheless, the only way for a fraction to equal zero is to have a zero numerator, i.e.

\dfrac{x}{x^3-2x^2+5x}=0\iff x=0

So, this function can't have zeroes, because the only point that would annihilate the numerator would annihilate the denominator as well.

Moreover, we have

\displaystyle \lim_{x\to 0} \dfrac{x}{x^3-2x^2+5x} = \lim_{x\to 0} \dfrac{x}{x(x^2-2x+5)} = \lim_{x\to 0} \dfrac{1}{x^2-2x+5} = \dfrac{1}{5}

So, we can't even extend with continuity this function in such a way that f(0)=0

5 0
3 years ago
Other questions:
  • S=6r2t<br><br>plz help 32 points
    14·1 answer
  • jessica and her 2 sisters want to take a camping trip. They have $225 saved. Each of them will save $21 a week until they have a
    14·2 answers
  • In<br> X = 4<br><br> Answer options; <br> A: x=e^4<br> B: x=(4/e)<br> C: x=4e<br> D: x=4^e
    7·1 answer
  • Log base 32 of 2<br> Help
    7·1 answer
  • point q is located at (18, 5). The x-coordinate of point r id half as much as the x-coordinate of point Q The y-coordinate of po
    13·1 answer
  • How do you write 97,200. in scientific notation?
    8·2 answers
  • A picture is 7 3/5 cm wide how much should it be trimmed to fit in a frame 7 3/10cm wide​
    15·2 answers
  • If necessary, round to the nearest tenth and label your answer <br>10ft <br>4ft <br><br><br>​
    12·1 answer
  • 4/10-3/10<br><br><br> how do i do this please hurryyyy
    5·1 answer
  • Sition book
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!