if you have already covered slopes, you could also get it that way, in fact is simpler that way.
Rectangular Prism Rectangular Pyramid Cylinder Cone ?????
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if you have already covered slopes, you could also get it that way, in fact is simpler that way.
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then
when will it reach the ground level? let's set s(t) = 0
part B) check the picture below
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then
when will it reach the ground level? let's set s(t) = 0
part B) check the picture below
Hello!
I have attached three graphs. The first one for x = 7, second one for y = -1, and third one with both x = 7 and y = -1 on the same graph.
Hope this helps :))
I have attached three graphs. The first one for x = 7, second one for y = -1, and third one with both x = 7 and y = -1 on the same graph.
Hope this helps :))