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castortr0y [4]
3 years ago
8

Rectangular Prism Rectangular Pyramid Cylinder Cone ?????

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0
If it’s rotating around something, it’s most likely a cylinder I believe
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Attached pic...please simplify
liraira [26]

Answer:

The answer is C

5 0
3 years ago
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What is the length of segment AB with point A and B located at (-4, 1) and (2, 9)
navik [9.2K]

Answer:

<h3>The answer is 10 units</h3>

Step-by-step explanation:

The distance between two points or a line segment can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, 1) and (2, 9)

The length of segment AB is

|AB|  =  \sqrt{ ({ - 4 - 2})^{2}  +  ({1 - 9})^{2} }  \\  =  \sqrt{( { - 6})^{2}  +   ({ - 8})^{2} }  \\  =  \sqrt{36 + 64}  \\  =  \sqrt{100}  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>10 units</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
Quadrilateral ABDE is a rectangle. DE = 4 in. and BD = 6 in. If the rectangle is rotated about a line through CF, cylinder Y is
postnew [5]

Answer:

1 in. is the answer.

Step-by-step explanation:

Solution: A Rectangle ABDE in which DE=4 inches and BD= 6 inches

 There are two kinds of rotations

1. one along the Breadth, side having length 6 inches,i.e rotated along line GH,  Cylinder Z is created.

Radius of cylinder Z=6/2= 3 inches

2. Second along the Length, Side having length 4 inches,i.e rotated about a line CF, cylinder Y is created.

Radius of cylinder Y= 4/2= 2 inches

Difference in Radii= Radius of cylinder Z  -  Radius of cylinder Y

                              =  3 - 2= 1 inches

Diagram shown below of both the cases:

7 0
3 years ago
Read 2 more answers
Solve for the unknown angle
Helga [31]

Answer:

30

Step-by-step explanation:

4 0
3 years ago
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LCM of two numbers is 1320 their HCF is 12 if one of the numbers is 132 find the other
guapka [62]

Answer:

<u>brainliest plzzzzzzzz</u>

120

Step-by-step explanation:

LCM=1320

(GDC) HCF=12

Another no.=132

let second no. be =A

According to question

First no.×Second no.=HCF×LCM

132×A=12×1320

132×A=15840

A=15840/132

A=120

Other no. is 120

5 0
3 years ago
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