3 years ago

If Anna gives Me half of her pumpkins and Coral half of whats left and she ends with 6 how many pumpkins did she start with?

2 answers:

7 0

Let's take x as the amount of pumpkins she have left

x=6
2×x=2x
=6×2
=12(after Anna gave me half of what she had)

12×2=24(what Anna had at first)

hope it helps! sorry if the answer is wrong

Gwar [14]3 years ago

6 0

X- the number of pumpkin she had initially
she gave you x/2
x-x/2=x/2
(x/2)/2=x/4(she gave Coral)
x/2-x/4=x/4
x/4=6
x=24

You might be interested in

10) On Tuesday Imani bought eight hats. On

SashulF [63]

34 I hope this helped!

6 0

2 years ago

the 2nd to 6th digits of the number 'b'. The number 'a': a.=.8381277236048455262835343009097967569917320013149981038679556930339

sattari [20]

Hhhhhhhhhmmmmmmmmmmmm

3 0

3 years ago

9.58 as a mixed number

tankabanditka [31]

9.58 = 9 58/100 = 9 29/50

4 0

3 years ago

Read 2 more answers

Calcula el opuesto y el inverso de cada uno de estos

Serjik [45]

Answer:

i think its a

Step-by-step explanation:

5 0

3 years ago

Simplify the following expression. cot^2x secx-cosx

Solnce55 [7]

ANSWER

$\cos(x) \cot ^{2} (x)$

EXPLANATION

The given expression is;

$\cot^{2} (x) \sec(x) - \cos(x)$

Change everything to

$\sin(x)$

and

$\cos(x)$

This implies that,

$\frac{ \cos^{2} (x) }{ \sin^{2} (x) } \times ( \frac{1}{ \cos(x) } )- \cos(x)$

Cancel the common factors,

$\frac{ \cos(x) }{ \sin^{2} (x) } \times ( \frac{1}{1} )- \cos(x)$

$\frac{ \cos(x) }{ \sin^{2} (x) }- \cos(x)$

$\frac{ \cos(x) - \sin ^{2} (x) \cos(x) }{ \sin^{2} (x) }$

$= \frac{ \cos(x)(1 - \sin ^{2} (x) ) }{ \sin^{2} (x) }$

$= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }$

$= \cos(x) \cot^{2} (x)$

6 0

2 years ago