X would equal 6 because 3/10=6/20. And 6/20 simplifies to 3/10
Answer:
p = $ 12521.82
Step-by-step explanation:
Interest Rate = 3.6 %, Compounding Frequency: Semi-Annual, Equivalent Annual Interest Rate
%
Number of Repayments is 11 with 10 being equal in magnitude and the last one being worth $ 270, the first repayment comes at the end of Year 2
Let $ p be the level payments that required. Therefore,
![100000 = p\times \frac{1}{0.0363} \times [1-\frac{1}{(1.0363)^{10}}] \times \frac{1}{(1.0363)} + \frac{270}{(1.0363)^{12}}](https://tex.z-dn.net/?f=100000%20%3D%20p%5Ctimes%20%20%5Cfrac%7B1%7D%7B0.0363%7D%20%5Ctimes%20%5B1-%5Cfrac%7B1%7D%7B%281.0363%29%5E%7B10%7D%7D%5D%20%5Ctimes%20%5Cfrac%7B1%7D%7B%281.0363%29%7D%20%2B%20%5Cfrac%7B270%7D%7B%281.0363%29%5E%7B12%7D%7D)
100,000 - 176.01 = p x 7.972
p = $ 12521.82
Answer:
The answer is equal!
Step-by-step explanation:
It's equal!
Hope this helped
Answer:
a) Only the first one is an identity.
Step-by-step explanation:
1). 8 cos O tan O csc O = 8 simplifies to:
cos O tan O csc O = 1
cos O * (sin O / cos O) * (1 /sin O)
= cos O sin O / cos O sin O
= 1
So it is identity.
2) 13 sec^2 O/ cos^2 O - tan^2 O / cos^2O
= 13 sec^2 O - tan^2 O / cos^2 O
Now sec^2 O = 1 + tan^2 O, so we have:
(13( 1 + tan^2 O) - tan^2 O) / cos^2 O
= (12 tan^2 O + 13) / cos^2 O
This is not always = 2 so its not an identity.