3 years ago

What would the median be if each of the students increased their sales by 3

Mathematics

1 answer:

Tanzania [10]3 years ago

5 0

Need more information

You might be interested in

H(x) = x3 - 2x<br> g(x) = 3x<br> Find (h – g)(x)

lord [1]

Answer:

x³ - 5x

Step-by-step explanation:

note (h - g)(x) = h(x) - g(x), thus

h(x) - g(x)

= x³ - 2x - 3x ← collect like terms

= x³ - 5x

4 0

3 years ago

Help for points quick pls

kotykmax [81]

$0.10 since you divide the price by the fluid ounce. (1.19/12=0.991...)

5 0

3 years ago

What equation do you get when you solve z - m = z + bx for x?

Arisa [49]

the answer is z-m=z+bx so z-m-z=bx and x=-mb

So it's the first option

the solution is x= - mb

6 0

4 years ago

Please provide an explanation and steps

likoan [24]

Haven't done one of these in forever. We avoid the quotient rule with an implicit logarithmic differentiation.

$y=\dfrac{(x^2+x+1)(x^3+2x+5)}{(2x-1)^5}$

$\ln y = \ln(x^2+x+1) + \ln(x^3+2x+5) - 5\ln(2x-1)$

Taking derivatives with respect to x,

$y'/y = \dfrac{2x+1}{x^2+x+1} + \dfrac{3x^2+2}{x^3+2x+5} - \dfrac{10}{2x-1}$

$y' = y \left( \dfrac{2x+1}{x^2+x+1} + \dfrac{3x^2+2}{x^3+2x+5} - \dfrac{10}{2x-1} \right)$

$y' = \dfrac{(x^2+x+1)(x^3+2x+5)(2x-1)}{(2x-1)^6} \left( \dfrac{2x+1}{x^2+x+1} + \dfrac{3x^2+2}{x^3+2x+5} - \dfrac{10}{2x-1} \right)$

$y'(2x-1)^6 =(2x+1)(x^3+2x+5)(2x-1)+(3x^2+2)(x^2+x+1)(2x-1) \\\quad -10(x^2+x+1)(x^3+2x+5)$

$y'=\dfrac{-7 x^4 - 16 x^3 - 51 x^2 - 70 x - 57}{(2x-1)^6}$

3 0

4 years ago

A right triangle has legs that measure 8 inches and 15 inches

Ksivusya [100]

<span>The length of the hypotenuse is 17 inches.</span>

4 0

4 years ago

Read 2 more answers