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vlabodo [156]
4 years ago
12

Which of the following are valid probability distributions for a discrete random variable

Mathematics
2 answers:
Radda [10]4 years ago
8 0
All of them except B and C.  Probabilities must add to 1 and none of the p's can be negative
Kipish [7]4 years ago
8 0

The valid probability distributions for a discrete random variable are :

<h2>Option A , D , and E</h2>

<h3>Further explanation</h3>

The probability of an event is defined as the possibility of an event occurring against sample space.

Let us tackle the problem.

In a discrete random variable , the sum of all the probability of distributions must equal to 1. The minimum value of probability is 0 and the maximum value of probability is 1.

<h2>Option A :</h2>

\frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{6}{6} = 1 ✔

This is the valid probability distributions for a discrete random variable

<h2>Option B :</h2>

\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = \frac{19}{20} \ne 1 ⤬

This is not the valid probability distributions for a discrete random variable

<h2>Option C :</h2>

-\frac{1}{2} - \frac{1}{3} - \frac{1}{4} - \frac{1}{5} + \frac{137}{60} = 1 ⤬

Although the sum is 1 but this is still not the valid probability distributions for a discrete random variable because probability cannot have negative values.

<h2>Option D :</h2>

\frac{1}{2} + \frac{1}{4} + \frac{1}{8} + ... + \frac{1}{128} = 1 ✔

This is the valid probability distributions for a discrete random variable

<h2>Option E :</h2>

\frac{1}{5} + \frac{1}{10} + \frac{1}{10} +...+ \frac{1}{10} = 1 ✔

This is the valid probability distributions for a discrete random variable

<h3>Learn more</h3>
  • Different Birthdays : brainly.com/question/7567074
  • Dependent or Independent Events : brainly.com/question/12029535
  • Mutually exclusive : brainly.com/question/3464581

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die

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Answer:

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Step-by-step explanation:

<u>Formula:</u> \frac{y2}{x2}  -  \frac{y1}{x1}  = m

m = slope.

<u>Substitute the given points into the formula:</u>

\frac{35}{16}  -  \frac{7}{5}  = m

<u>Solve:</u>

\frac{35}{16}  -  \frac{7}{5}  =  \frac{28}{11}  = 2 \frac{6}{11}

8 0
2 years ago
-9+n=-18 step by step solution
valentinak56 [21]
Step 1: -9+n=-18. You would add the inverse to both sides, meaning you’d add nine to the negative nine to cancel it out and then then 9 to -18.

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3 0
3 years ago
A simple random sample of 25 filtered 100mm cigarettes is obtained, and the tar content of each cigarette is measured. The sampl
zaharov [31]

Answer:

A) -1.40

B) -1.71

C) 0.0872

Step-by-step explanation:

Sample size = n = 25

Sample mean = x = 20.2 mg

Sample standard deviation = s = 3.21 mg

Claim: Sample mean is less than 21.1 mg

So, u = 21.1

Null Hypothesis: u ≥ 21.1 mg

Alternate Hypothesis? u < 21.1 mg

Since we have the sample standard deviation, we will use the t-distribution to answer this question

Part A) t-test statistic

The formula to calculate the t-test statistic is:

t=\frac{x-u}{\frac{s}{\sqrt{n} } }

Using the values, we get:

t=\frac{20.2-21.1}{\frac{3.21}{\sqrt{25} } }\\\\ t=-1.40

Thus, the value of t-test statistic is -1.40

Part B) Critical Value

In order to calculate the critical value we need the value of significance level and the number of degrees of freedom.

Degrees of freedom = df = n -1 = 25 - 1 = 24

Using t-table or t-critical value calculator for significance level 0.05 and 24 df the value comes out to be:

t-critical = -1.71

Since this is a left tailed test, we have considered the negative t-critical value. Rejection region will be the values less than -1.71 i.e. values which lie to left of -1.71

Part C) P-value

In order to calculate the P-value we need the t-score which we calculated in part A and the degrees of freedom.

Using the t-table or p value calculator the p value for t score of -1.40 and df 24 comes out to be:

p-value = 0.0872

Conclusion:

Since the p-value is larger than the significance level, we fail to reject the claim.

Also the test-statistic does not lie in the rejection region, so another hint that we cannot reject the claim.

Thus, no conclusion can be drawn about the effectiveness of the filters using these tests.

3 0
3 years ago
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FrozenT [24]
If im not wrong...D.... would be the answer
5 0
3 years ago
Casey spends $50 a week on entertainment. Kelly spends 10% less than Casey and Megan spends $5 less than Kelly. Which expression
Dahasolnce [82]
Hey there,

Answer:

Casey = $50
Kelly = $50 - (10% x $50)
        = $50 - $ 5 
        = $45
Megan = $45 - $5
           = $40

Hope this helps :D

<em>~Top</em>
8 0
4 years ago
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