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vlabodo [156]
3 years ago
12

Which of the following are valid probability distributions for a discrete random variable

Mathematics
2 answers:
Radda [10]3 years ago
8 0
All of them except B and C.  Probabilities must add to 1 and none of the p's can be negative
Kipish [7]3 years ago
8 0

The valid probability distributions for a discrete random variable are :

<h2>Option A , D , and E</h2>

<h3>Further explanation</h3>

The probability of an event is defined as the possibility of an event occurring against sample space.

Let us tackle the problem.

In a discrete random variable , the sum of all the probability of distributions must equal to 1. The minimum value of probability is 0 and the maximum value of probability is 1.

<h2>Option A :</h2>

\frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{6}{6} = 1 ✔

This is the valid probability distributions for a discrete random variable

<h2>Option B :</h2>

\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = \frac{19}{20} \ne 1 ⤬

This is not the valid probability distributions for a discrete random variable

<h2>Option C :</h2>

-\frac{1}{2} - \frac{1}{3} - \frac{1}{4} - \frac{1}{5} + \frac{137}{60} = 1 ⤬

Although the sum is 1 but this is still not the valid probability distributions for a discrete random variable because probability cannot have negative values.

<h2>Option D :</h2>

\frac{1}{2} + \frac{1}{4} + \frac{1}{8} + ... + \frac{1}{128} = 1 ✔

This is the valid probability distributions for a discrete random variable

<h2>Option E :</h2>

\frac{1}{5} + \frac{1}{10} + \frac{1}{10} +...+ \frac{1}{10} = 1 ✔

This is the valid probability distributions for a discrete random variable

<h3>Learn more</h3>
  • Different Birthdays : brainly.com/question/7567074
  • Dependent or Independent Events : brainly.com/question/12029535
  • Mutually exclusive : brainly.com/question/3464581

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die

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Please help.........​
Alex

Answer:

- \frac{61}{11}

Step-by-step explanation:

\frac{x}{y} = \frac{5}{6} ( cross- multiply )

6x = 5y ( divide both sides by 6 )

x = \frac{5}{6} y

Then

\frac{5x+6y}{5x-6y} ← substitute x = \frac{5}{6} y into the expression

= \frac{\frac{25}{6}y+6y }{\frac{25}{6}y-6y }

= \frac{\frac{61}{6}y }{-\frac{11}{6}y }

= \frac{\frac{61}{6} }{-\frac{11}{6} }

= \frac{61}{6} × - \frac{6}{11}

= - \frac{61}{11}

3 0
3 years ago
What is the value of the expression below when y = 7?<br> 2y^2 + 9y + 2<br><br><br> Help me!!!!!
Flauer [41]

Answer:

163

Step-by-step explanation:

2*(7^{2}) +9(7)+2

2*(49)+9(7)+2

98+63+2

=163

8 0
3 years ago
When will n(A∩B)=0? Explain and give an example.
andrew11 [14]

Answer:

Two sets are called disjoint if they have no elements in common. For example:

The sets S = { 2, 4, 6, 8 } and T = { 1, 3, 5, 7 } are disjoint.

Another way to define disjoint sets is to say that their intersection is the empty set,

Two sets A and B are disjoint if A ∩ B = 0.

In the example above,

S ∩ T = ∅ because no number lies in both sets.

Step-by-step explanation:

8 0
3 years ago
6/15 divided by 1/7
mylen [45]
Question-
6/15 divided by 1/7

Answer-
Find the reciprocal of the divisor
Reciprocal of 1/7: 7/1Now, multiply it with the dividend
So, 6/15 ÷ 1/7 = 6/15 × 7/1= (6 × 7)/(15 × 1) = 42/15After reducing the fraction, the answer is 14/5In mixed form: 2 4/5
6 0
3 years ago
Read 2 more answers
Please help quick!!!​
hodyreva [135]

Answer:

I wanna say 35 \cm

Step-by-step explanation:

6 0
3 years ago
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