We use the equation for repeated trials written below:
Probability = n!/r!(n-r)! * p^(n-r) * q^r
The p is the probability of getting a side A in one toss. Since a counter has only two side, p = 0.5. The q is the probability of not getting side A in one toss, which is also q = 0.5. Now, r is the number of success per n trials. There are 3 tosses so, n=3. The question is getting "at least 1" counter. So, r=1, r=2 and r=3.
Probability for r=1: 3!/1!(3-1)! * (0.5)^(3-1) * (0.5)^1= 0.375
Probability for r=2: 3!/2!(3-2)! * (0.5)^(3-2) * (0.5)^2= 0.375
Probability for r=1: 3!/3!(3-3)! * (0.5)^(3-3) * (0.5)^3= 0.125
Total probability = 0.375 + 0.375 + 0.125 = 0.875
Answer:6.28
Step-by-step explanation:
C=pi*diameter
C=3.14*2
C=6.28
Answer: 7,824
Step-by-step explanation:
What kind of question is this lol, it took me forever.
Answer:
x=1
Step-by-step explanation:
8x+6+2x=12+4x
10x+6=12+4x
-6 -6
10x=6+4x
-4x -4x
6x=6
x=1
The answer is 176.44
9,800
