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3 years ago

15

Pampered Pooch charges $5 for one hour of Doggy Daycare $10 for two hours and fifteen dollars for 3 hours what is the rate chang

e

1 answer:

DochEvi [55]3 years ago

4 0

Answer:

$5 difference in rate at each step or change in hours.

Step-by-step explanation:

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If the nth term of a number sequence is n² – 3, find the first 3 terms and the 10th term

nignag [31]

Answer:

-2, 1, 6 and 97

Step-by-step explanation:

Tn = n² - 3

First Term : T1 = (1)² - 3 = -2

Second Term : T2 = (2)² - 3 = 1

Third Term : T3 = (3)² - 3 = 6

Tenth Term : T10 = (10)² - 3 = 97

6 0

3 years ago

The region bounded by the curve y = 2/(1 + e−x), the x- and y-axes, and the line x = 10 is rotated about the x-axis. Use Simpson

sp2606 [1]

Answer:

21 darted to the nearest 10

Step-by-step explanation:

idk lol, sorry please don't report have great night or day where ever you live :D

4 0

3 years ago

An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,

butalik [34]

Answer:

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

$r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t$

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

$s=\sqrt{r_{A}^{2}+r_{B}^{2}}$

Rate of change of such distance can be found by the deriving the expression in terms of time:

$\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }$

Where $\frac{dr_{A}}{dt} = 500\,\frac{mi}{h}$ and $\frac{dr_{B}}{dt} = 550\,\frac{mi}{h}$ , respectively. Distances of each airliner at 2:30 PM are:

$r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi$

$r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi$

The rate of change is:

$\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }$

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

6 0

3 years ago

Name the plane that contains A, B, and C

torisob [31]

Step-by-step explanation:

Plane S contains points A, B and C while Plane T contains points A, D and E.

Hence the answer is Plane S.

4 0

3 years ago

I need help with this

emmasim [6.3K]

Answer:

Here,

Angle TUV + Angle NUV=TUV

By substituting the provided or given value ls in the question we obtain,

1+38x+66 Degree= 105x

1+66 Degree= 67x

67 Degree= 67x

1 Degree = x

x = 1 Degree

Therefore

Angle TUN=1+38x=39

Angle NUV=66 Degree

Therefore

1+38x+66 Degree= 105x

=39 Degree+66 Degree= 105 Degree

Therefore

Angle TUV=105 Degree

6 0

3 years ago