For the answer to the question above, to solve the average increase between hours 2 and 4, first let as solve the the number of student in each hour
x = 2f(x) = 4x -1f(2) = 4(2) - 1f(2) = 7
x = 3f(x) = 4x -1f(3) = 4(3) - 1f(3) = 11
x = 4f(x) = 4x -1f(4) = 4(4) - 1f(4) = 15
increase in hours 2 to 4increase per hour = 15 - 7 / 4 - 2increase per hour = 4 students per hour
L think the answer is - 1315
Answer:
no solution
-6 ≠ 2
Step-by-step explanation:
y = 2x + 6
2x - y = 2
substitute for y:
2x - (2x + 6) = 2
combine like terms:
-6 ≠ 2
(5y+6y)+(4x+8y)+(1z-5y)=
5y+6y+4x+8y+1z-5y=
14y+4x+1z
Melissa combined unlike terms