Answer:
C. Isosceles Triangle
Step-by-step explanation:
An Isosceles triangle is a type of triangle in geometry that has two sides of equal length.
From the figure attached, triangle STR has two sides of equal length which are;
1.) ST and
2.) TR
The two equal sides (ST and TR) are called legs while the third side is called the base of the triangle.
*P.S: I believe your question is based on the image attached
Answer:
38
Step-by-step explanation:
3x + 2y when X=10 and y=4
3(10) + 2(4)
30 + 8
38
Average rate= change in alt / change in time
r=-378/7=-54ft/min
Answer:
A) 
B) - 5
C) Not Possible
D) 5
E) 
- Step-by-step explanation:
- All integers are rational numbers. But not all rational numbers are integers.
- All whole numbers are integers. But not all integers are whole numbers.
I am a rational number but not an integer. Located on the right of 0.
This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form
.
From, the options
would fit this description.
I am a rational number and an integer but not a whole number.
This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.
I am a whole number but not an integer.
This is clearly not possible because all whole numbers are a subset of integers.
I am a rational number, a whole number and an integer.
This means it is a positive integer. 5 would fit this description.
I am a rational number but not an integer; located on the left side of 0.
This means it is a negative number.
should be the answer.
Answers:
A.) 8 is the outlier in the set. It is the only number that doesn't match with the others. It is the furthest from the median of the numbers.
B.) The outlier could represent false information. It could greatly drop the number of the mean, or the average, range of the scores.
C.) The mean is affected more. The mean of a set of numbers is the average of the set. The median just locates the middle-most number. The median would not always give an accurate representation of the average of the set like the mean would.