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3 years ago

On Monday, I bought 1 dog and 3 cats for a total cost of $7.75. On Tuesday, 1

Mathematics

1 answer:

Zina [86]3 years ago

4 0

Answer: The cats cost more

also there is a typo

Step-by-step explanation:

I bought 1 dog and 3 cats a total cost of $7.75. the three cats cost more so in all the cats must cost 3.56$

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2 years ago

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A rope is swinging in such a way that the length of the arc is decreasing geometrically. If the first arc is 18 feet long and th

NemiM [27]

Answer: The length of the second arc is 12 feet.

Step-by-step explanation:

Since we know that

A rope is swinging in such a way that the length of the arc is decreasing geometrically,

Length of first arc = 18 feet

Length of third arc = 8 feet

Let the length of second arc be x

As we know that

$\frac{a_2}{a_1}=\frac{a_3}{a_2}\\\\\frac{x}{18}=\frac{8}{x}\\\\x^2=18\times 8\\\\x^2=144\\\\x=\sqrt{144}\\\\x=12$

Hence, the length of the second arc is 12 feet.

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3 years ago

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Anjana has 4 pencil in her box. Their average length is 10cm. Which of the following is NOT POSSIBLE? A) The shortest pencil in

Troyanec [42]

The situation which is not possible about the pencils in her box is; Choice B: The longest pencil in the box is 8cm long.

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By convention, the mean is a statistical measure of central tendency.

On this note, if the mean of a set of data values is 10, this means the data values have data points greater, equal and less than the mean value.

On this note, it is impossible to have the longest pencil in the box to have a length, 8cm.

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2 years ago

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DanielleElmas [232]

Answer: I think it is 40%

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3 years ago

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A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee

madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

$nC_r=\frac{n!}{r!(n-r)!}$

Using the formula

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

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3 years ago