All categories

3 years ago

On Monday, I bought 1 dog and 3 cats for a total cost of $7.75. On Tuesday, 1

Mathematics

1 answer:

Zina [86]3 years ago

4 0

Answer: The cats cost more

also there is a typo

Step-by-step explanation:

I bought 1 dog and 3 cats a total cost of $7.75. the three cats cost more so in all the cats must cost 3.56$

You might be interested in

Tony had a certain number of stamps that were each worth $0.15. He misplaced 7 stamps. He found that the total value of his stam

erica [24]

The Value Of S Is 100 or $1.00 or if you add it with the stamp collection then it'll be $6.55.

6 0

3 years ago

What is the slope of the line that contains these points?

ryzh [129]

Answer:

-8

Step-by-step explanation:

Apply slope/gradient formula: (12 - 36)/(11 - 8) = -24/3 = -8

This is a question on coordinate geometry. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), I have already posted the slope formula which you may want to save it for future reference and I'll also post some of my own notes on certain topics and also some tips that may be useful to you :)

6 0

3 years ago

CAN SOMEONE HELP ME PLZZZZZZZZZZZZ

N76 [4]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Let f(x)=(3)x−3. Evaluate f(0) without using a calculator.

Alexandra [31]

Answer:f(0)=-3

Step-by-step explanation:

f(x)=3x-3

f(0)=3(0)-3

f(0)=0-3

f(0)=-3

5 0

3 years ago

Read 2 more answers

Factor completely, then place the answer in the proper location on the grid.

Tresset [83]

$\mathrm{Factor\:out\:common\:term\:}9 \ \textgreater \ 9\left(x^4-25y^8\right)$

$Factor \ \textgreater \ x^4-25y^8$

$\mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$
$x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

$x^2-5y^4 \ \textgreater \ \mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$
$x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

$\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

$9\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

Hope this helps!

8 0

3 years ago