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3 years ago

Find the area of the shaded region

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Answer:

51 ft²

Step-by-step explanation:

The shaded area is the area of the triangle subtract the area of the rectangle.

The area (A) of the triangle is calculated as

A = $\frac{1}{2}$ bh ( b is the base and h the perpendicular height )

Here b = 11 and h = 10, thus

A = 0.5 × 10 × 11 = 5 × 11 = 55 ft²

Area of rectangle = 1 × 4 = 4 ft², hence

Area of shaded region = 55 - 4 = 51 ft²

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How to set up a system of equations

Scorpion4ik [409]

To set up your system of equations is to have 2 equations. They both would have 1 similar variable. For example, Jenny is 5 more her brother's age. She is also 2 more than twice her brother's age. You would set this up as Y, which is Jenny, and X, her brother. Y = 5 + x and Y = 2x + 2. Make sure you put Y in the same spot in both equations. Then take the other half of the equations and simplify them. 5 + x = 2x + 2. Subtract x from both sides to get 5 = x + 2. Subtract 2 from both sides to get 3 = x. Now replace the X from both equations to get Y = 5+3, and Y = 2(3) + 2. You will see both add up to 8, which is how old Jenny is in this example. Hope this helped!

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2 years ago

What is the slope of a line perpendicular to the line whose equations is x-y=6

belka [17]

Answer:

m = -1

Step-by-step explanation:

First write the line in slope intercept form y = mx+b where m is the slope and b is the y intercept

x-y = 6

subtract x from each side

-y = -x+6

Multiply each side by -1

y = x-6

The slope is 1

Perpendicular lines have slopes that multiply to -1

m * 1 = -1

m = -1

The slope of the perpendicular line is -1

6 0

2 years ago

A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?

Travka [436]

Answer:

$area=\frac{85}{4}feet^{2}$

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

$perimeter=18\frac{1}{2}\\\\length=5$

$2(length+width)=perimeter$

Substitute,

$2(5+width)=18\frac{1}{2}$

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

$2(5+width)=\frac{37}{2}$

Inverse operations,

$2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}$

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

$length=5\\\\width = \frac{17}{4}$