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3 years ago

Find the area of the shaded region

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Answer:

51 ft²

Step-by-step explanation:

The shaded area is the area of the triangle subtract the area of the rectangle.

The area (A) of the triangle is calculated as

A = $\frac{1}{2}$ bh ( b is the base and h the perpendicular height )

Here b = 11 and h = 10, thus

A = 0.5 × 10 × 11 = 5 × 11 = 55 ft²

Area of rectangle = 1 × 4 = 4 ft², hence

Area of shaded region = 55 - 4 = 51 ft²

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Answer:

$1.28

Note for you:

I hope this helps!

Answer and Step-by-step explanation:

The computation is shown below;

As we know that

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Simple interest = Principal × rate × time

For Account A, the principal would be

2 = Principal × 3.2% × 3

So, the principal is $20.83

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For account 1

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1 year ago

What is symmetrical line

Delicious77 [7]

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2 years ago

PLEASE HELP ASAP!!!

EleoNora [17]

<span>Part 1:

$(x+1)^2-3(x+2) \\ \\ =x^2+2x+1-3x-6 \\ \\ =x^2-x-5$

option b.

Part 2:
$(5x^3y^{-3})(-6x^4y)\\ \\=5(-6)x^{3+4}y^{-3+1}\\ \\=-30x^7y^{-2}\\ \\=\frac{-30x^7}{y^2}$

option d

Part 3:
$\frac{8+x}{2} - \frac{x+3}{3} =4$

Multiply through by the LCM of 2 and 3 (i.e. 6)
$6\left(\frac{8+x}{2}\right) - 6\left(\frac{x+3}{3}\right) =6(4) \\ \\ 3(8+x)-2(x+3)=24 \\ \\ 24+3x-2x-6=24 \\ \\ x+18=24 \\ \\ x=24-18=6$

option b

Part 4
x^2-3x-8=x+4

$x^2-3x-8=x+4 \\ \\ x^2-3x-x-8-4=0 \\ \\ x^2-4x-12=0 \\ \\ (x-6)(x+2)=0 \\ \\ x=6 \ or \ -2$

option d

Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?

In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.

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option d.
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2 years ago

Find the area of the shaded region​

Find the area of the shaded region