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3 years ago

What is the solution to the equation 6x = 39?

Mathematics

1 answer:

SashulF [63]3 years ago

8 0

Answer:

6.5

Step-by-step explanation:

39/6 comes out to 6.5

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6(3X +5 ) = 7(2x +2)

boyakko [2]

Answer:

X=-4 last answer i got i hope it is helpful have a nice day

Step-by-step explanation:

Let's solve your equation step-by-step.

6(3x+5)=7(2x+2)

Step 1: Simplify both sides of the equation.

6(3x+5)=7(2x+2)

(6)(3x)+(6)(5)=(7)(2x)+(7)(2)(Distribute)

18x+30=14x+14

Step 2: Subtract 14x from both sides.

18x+30−14x=14x+14−14x

4x+30=14

Step 3: Subtract 30 from both sides.

4x+30−30=14−30

4x=−16

Step 4: Divide both sides by 4.

−16

x=−4

Answer:

x=−4

5 0

3 years ago

Read 2 more answers

What value of x makes the equation 3 = <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3x%2B%206%7D" id="TexFormula1" title="

disa [49]

3^3=3x+6,so3x=27-6=21,sox=7

3 0

3 years ago

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Given that a function, g, has a domain of -20 sxs 5 and a range of -5 s g(x) s 45 and that g(0) = -2 and g(-9) = 6, select the s

musickatia [10]

Answer:

Step-by-step explanation:

other options lie outside the domain and range

3 0

3 years ago

!!!!!!!!!!!!!!!!!!!!

Andru [333]

Answer:

$f^{-1}(x)=4x+20$

Step-by-step explanation:

<u>Given</u>

<u /> $f(x)=\frac{x}{4}-5\\ \\y=\frac{x}{4}-5$

<u>Swap x and y and solve for y</u>

<u /> $y=\frac{x}{4}-5\\ \\x=\frac{y}{4}-5\\ \\x+5=\frac{y}{4}\\ \\4(x+5)=y\\\\y=4x+20$

<u>Final answer</u>

<u /> $f^{-1}(x)=4x+20$

Keep in mind that we need to swap the variables because a function and its inverse are symmetrical about the line y=x. See the graph below.

3 0

2 years ago

HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r

lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression $2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)$

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

$= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\$

Then we find the LCM of the resulting function

$= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\= \frac{7x}{10} + 2\frac{1}{2}y+6\\$

The final expression gives the required answer

7 0

2 years ago