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lawyer [7]
3 years ago
5

16+5x=8x-5 What would the variable be?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0
16+5x =8x-5

Reorder the terms
16+5x = -5+8x
Solving for variable for x

Move all terms containing x to the left, all other terms to the right.
Add -8x to each side of the equation.
16+ -3x = -5 + 8x + -8x

Combine like terms: 5x + -8x=-3x
16+-3x = -5 + 8x + -8x

Combine like terms: 8x + -8x = 0
16+-3x = -5 + 0
16+ -3x = -5

Add -16 to each side of the equation
16+-16 + -3x = -5 + 16

Combine like terms: 16+ -16 = 0
0 + -3x =-5 + -16
-3x = -5 + -16

combine like terms: -5 + -16 = -21
-3x = -21
Divide each side by -3
x=7


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Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-5, -2) and point (8, -3) rounded
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Option D: 13 units is the distance between the two points

Explanation:

Given that the points are (-5,-2) and (8,-3)

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The distance between the two points can be determined using the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let us substitute the points (-5,-2) and (8,-3) in the above formula, we get,

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Simplifying the terms within the bracket, we have,

d=\sqrt{(8+5)^2+(-3+2)^2}

Adding the terms within the bracket, we get,

d=\sqrt{(13)^2+(-1)^2}

Squaring the terms, we have,

d=\sqrt{169+1}

Adding, we get,

d=\sqrt{170}

Simplifying, we have,

d=13.04

Rounding off to the nearest tenth, we get,

d=13.0 \ units

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