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Bingel [31]
4 years ago
15

What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

Mathematics
2 answers:
ololo11 [35]4 years ago
6 0

Answer: x\geq -2

Step-by-step explanation:

Given the inequality 2(3x - 1) \geq 4x -6 you need to solve for "x".

Apply Distributive property on the left side of the equation:

 6x - 2 \geq 4x -6

Now add 2 to both sides:

 6x - 2+(2) \geq 4x -6+(2)

 6x \geq 4x -4

The next step is to subtrac 4x from both sides:

 6x-(4x) \geq 4x -4-(4x)

 2x \geq -4

And finally, divide both sides by 2:

\frac{2x}{2}\geq  \frac{-4}{2}\\\\x\geq -2

Angelina_Jolie [31]4 years ago
5 0

For this case we must find the value of the variable "x" of the following expression:

2 (3x-1) \geq4x-6

We apply distributive property to the terms within parentheses: 6x-2 \geq4x-6

We subtract 4x on both sides:

6x-4x-2 \geq-6\\2x-2 \geq-6

We add 2 to both sides:

2x \geq-6 + 2\\2x \geq-4

We divide between 2 on both sides:

x \geq \frac {-4} {2}\\x \geq-2

Answer:

x \geq-2

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