Answer:
9a-b
Step-by-step explanation:
1) 3 (5a - b) - 2 (3a - b)
15a - 3b - 2 (3a - b)
2) 15a - 3b - 2 (3a - b)
15a - 3b - 6a + 2b
3) 15a - 3b - 6a + 2b
9a - 3b + 2b
4) 9a + 3b + 2b
9a - b
Answer:
156
Step-by-step explanation:
There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
_____
C(n,k) = n!/(k!(n-k)!)
Answer:
-1/5
Step-by-step explanation:
