All categories

2 years ago

Chris can be paid in one of two ways. Plan A is a salary of $400 per month, plus

Mathematics

1 answer:

Makovka662 [10]2 years ago

6 0

Answer:

$7300

Step-by-step explanation:

For Chris to select plan A, Plan A salary should be greater than that of plan B. Let the amount of sales be x

$400 + \frac{7}{100} x > 692 + \frac{3}{100} x \\ \frac{7}{100} x - \frac{3}{100} x > 692 - 400 \\ \frac{4}{100} x > 292 \\ x > 7300$

You might be interested in

Is this correct plz help me

Lina20 [59]

Answer: Yes!

Step-by-step explanation:

You correctly answered!

4 0

3 years ago

Find in the triangle. Round to the nearest degree. a. 45° C. 60° b. 59° d. 42°

aleksklad [387]

Answer:

Theta = 59 degrees

Step-by-step explanation:

Here, we want to get the value of the marked angle

To do this, we use the appropriate trigonometric ratio

From what we have,

The side 42 ft is adjacent the angle given

The side facing the right angle is 82 ft

The trigonometric ratio that connects the adjacent and the hypotenuse is cosine. It is the ratio of the adjacent to the hypotenuse

Cos theta = 42/82

theta = cos^-1 0.5122

theta= 59.189

To the nearest degrees, this is 59 degrees

6 0

3 years ago

Brody added a fraction to 5/6 to get 31/30. Use the equation a/b + c/d = (ad +bc)/ bd to find the fraction he added

sashaice [31]

The fraction he added is 6/30, or 1/5.
I'm not 100% sure about the equation you want me to use but I did the work this way:

5/6+x/30=31/30 (the denominator has to equal 30 because you are adding. You need a common denominator which is why you need to change 5/6. We can label the numerator as a hidden value x)

25/30+x=31/30

You can then work backwards and basically subtract 25 from 31 and get 6; so x=6

8 0

3 years ago

I don't understand any of these questions

Xelga [282]

20 because there are many more

6 0

3 years ago

Read 2 more answers

Determine which of these sequences is an arithmetic sequence. Then determine the explicit formula that would be used to define t

vagabundo [1.1K]

34, 43, 52, 61, ...

43-34 = 9; 52-43 = 9; 61-52 = 9

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 34

difference: d = 9

so the formula:

$a_n=a+d(n-1)\\\\a_n=34+9(n-1)\\\\a_n = 34+9n-9\\\\\underline{a_n=9n+25}$

10, 6, 2, -2, ...

6-10 = -4; 2-6 = -4; -2-2 = -4

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 10

difference: d = -4

so the formula:

$a_n=a+d(n-1)\\\\a_n=10+(-4)(n-1)\\\\a_n = 10-4n+4\\\\\underline{a_n=-4n+14}$

-3, -10, -17, -24, ...

-10-(-3) = -7; -17-(-10) = -7; -24-(-17) = -7

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = -3

difference: d = -7

so the formula:

$a_n=a+d(n-1)\\\\a_n=-3+(-7)(n-1)\\\\a_n =-3-4n+7\\\\\underline{a_n=-7n+4}$

7, 8.5, 10, 11.5, ...

8.5-7 = 1.5; 10-8.5 = 1.5; 11.5-10 = 1.5

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 7

difference: d = 1.5

so the formula:

$a_n=a+d(n-1)\\\\a_n=7+1.5(n-1)\\\\a_n =7+1.5n-1.5\\\\\underline{a_n=1.5n+5.5}$

10)

30, 22¹/₂, 15, 7¹/₂, ...

22¹/₂-30 = -7¹/₂; 15-22¹/₂ = -7¹/₂; 7¹/₂-15 = -7¹/₂

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 30

difference: d = -7¹/₂

so the formula:

$a_n=a+d(n-1)\\\\a_n=30+(-7\frac12)(n-1)\\\\a_n =30-7\frac12n+7\frac12\\\\ \underline{a_n=-7\frac12n+37\frac12}$

6 0

2 years ago