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vova2212 [387]
3 years ago
10

Lest year, the enrollment at a local middle school was 865 students. Determine the percent of change and state if it is increase

or decrease. ( round your percent to the nearest tenths place. )
Mathematics
1 answer:
babymother [125]3 years ago
8 0
870 865 is rounded up to 870
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Please help i really really need it, please don’t answer if you don’t know
docker41 [41]

Answer:

1. a=2, b=3 c=4

2.b

3. mean= 29, median=30, all are mode, range=21

Step-by-step explanation:

5 0
3 years ago
in 1985, there were 285 cell phone subscribers in the small town of Centerville. the number of subscribers increased by 75% per
Vladimir79 [104]

Answer:

  43,872

Step-by-step explanation:

The growth of cell phone subscribers in Centerville can be modeled by an exponential function.

  y = ab^x . . . . . where a = initial value, b = growth factor

The growth rate is given as 75% per year, so x will have units of years. It will be zero for the year 1985. The growth factor is ...

  b = 1 + growth rate = 1 +0.75 = 1.75

Then the model is ...

  y = 285·1.75^x

__

For x = 1994 -1985 = 9, the number of subscribers is modeled as ...

  y = 285·1.75^9 ≈ 43,872

The model predicts 43,872 cell phone subscribers in 1994.

7 0
2 years ago
Find the value of yy in each equation. Explain how you determined the value of y.
Hitman42 [59]

Answer:

a) 3

b) 9

c) 81

d) x

Step-by-step explanation:

We know the properties of log function as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = \log(A)+\log(B)

3) log(aᵇ) = b × log(a)

also,

4) \log_b(a)=\frac{\log(a)}{\log(b)}

Given:

a. y = 3^{\log_3(3)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(3)})

using 3, we get

log(y) = log₃(3) × log(3)

using 4, we get

log(y) =  \frac{\log(3)}{\log(3)} × log(3)

or

log(y) =  1 × log(3)

taking anti-log both sides

y = 3

b. y = 3^{log_3(9)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(9)})

using 3, we get

log(y) = log₃(9) × log(3)

using 4, we get

log(y) =  \frac{\log(9)}{\log(3)} × log(3)

or

log(y) = log(9)

taking anti-log both sides

y = 9

c. y = 3^{\log_3(81)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(81)})

using 3, we get

log(y) = log₃(81) × log(3)

using 4, we get

log(y) =  \frac{\log(81)}{\log(3)} × log(3)

or

log(y) =  log(81)

taking anti-log both sides

y = 81

d. y = 3^{\log_3(x)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(x)})

using 3, we get

log(y) = log₃(x) × log(3)

using 4, we get

log(y) =  \frac{\log(x)}{\log(3)} × log(3)

or

log(y) =  log(x)

taking anti-log both sides

y = x

3 0
3 years ago
The ratio of star beads to moon beads in a bracelet is 9:6.
Arlecino [84]
So for every 9 star beads you have, you have 6 moon beads. The rule is dividing.
6 divided by two (because we have two moon beads) is 3.
9 divided by three (because that's the answer to the first part) is 3.
So there are 3 star beads.
6 0
3 years ago
1<br> What is the solution of<br> 1, 12<br> +<br> х<br> 3 5<br> 15
Mashcka [7]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
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