$\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_6(5x)+\log_6(2)=5\implies \log_6(5x\cdot 2)=5\implies \log_6(10x)=5 \\\\\\ 6^{ \log_6(10x)}=6^5\implies 10x=6^5\implies x = \cfrac{6^5}{10}\implies x = \cfrac{3888}{5}\implies x = 777.6$

8 0

3 years ago

For a field trip, the school bought 47 sandwiches for $4.60 each and 39 bags of chips for $1.25 each. How much did the school sp

NNADVOKAT [17]

Answer: $\$264.95$

Step-by-step explanation:

You know that 1 sandwich costs $4.60 and the school bought 47 sandwiches.

Therefore, in order to calculate the total cost of 47 sandwiches, you need to multiply this number of sandwiches bought by the schoole, by the cost of 1 sandwich. Then:

$sandwiches=(47)(\$4.60)\\\\sandwiches=\$216.2$

You know that 1 bag of chip costs $1.25 and the school bought 39 bags of chips.

So, in order to calculate the total cost of 39 bags of chips, you must multiply the total number of them bought by the school, by the cost of 1 bag of chips.

Then:

$bag\ of\ chips=(39)(\$1.25)\\\\bag\ of\ chips=\$48.75$