White 15/45 in simplest form

I GRADUATE AFTER THIS ONE PLEASE HELP

soldi70 [24.7K]

A hyperbola is formed

3 0

3 years ago

Read 2 more answers

How many fluid ounces of water will a 6-cup measuring cup hold ?

Dafna11 [192]

48 fluid ounces. There's 8 oz in one cup:)

4 0

3 years ago

Read 2 more answers

Jeremy lost his dog, and wants to make some signs to put up in the neighborhood. The cost to make 8 paper signs and 2 laminated

Mashcka [7]

Answer:

cost to make paper signs = $1

cost to make laminated signs = $2

Step-by-step explanation:

Let

x = cost to make paper signs

y = cost to make laminated signs

8x + 2y = 12 (1)

10x + 10y = 30 (2)

Multiply (1) by 5

40x + 10y = 60 (3)

10x + 10y = 30 (2)

Subtract (2) from (3) to solve for x

40x - 10x = 60 - 30

30x = 30

x = 30/30

x = $1

Substitute x = 1 into (1)

8x + 2y = 12

8(1) + 2y = 12

8 + 2y = 12

2y = 12 - 8

2y = 4

y = 4/2

y = $2

cost to make paper signs = $1

cost to make laminated signs = $2

5 0

3 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

1. A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin; 2. The radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball; 3. The volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

or

$\\ 1 \leq a < 10$ (3)

Then, b represents the order of magnitude of such a number (Order of magnitude (2020), in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The La Plata river dolphin weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the scientific notation):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin.

<h3>Second case</h3>

Following the same reasoning, we can conclude that the radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball:

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$