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Advocard [28]
3 years ago
12

The scatter plot shows the number of hats and scarves each knitter sold at a knitting show.

Mathematics
2 answers:
SOVA2 [1]3 years ago
4 0

I believe your answer should be 5!

Nostrana [21]3 years ago
3 0

Answer:

Option B) 5    

Step-by-step explanation:

We are given the following information:

A scatter plot is given which shows the number of hats and scarves each knitter sold at a knitting show.

In the scatter plot the x-axis shows the number of hats sold and the y-axis shows the number of scarves sold.

We have to find the number of hats sold by the knitter when he sold 8 scarves.

In order to find this we have to find the x-values corresponding to the y-values of 8 scarves in the scatter plot.

Corresponding to 8 on y-axis we have a point that have a corresponding value of 5.

Hence, 5 hats were sold by the knitter when he sold 8 scarves.

Option B) 5 is the correct answer.

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What is 30% of 70 for big ideas math
VashaNatasha [74]

Answer:

21

Step-by-step explanation:

30 Percent of 70 could be written .3 × 70. .3 times 70 is 21

3 0
3 years ago
The distance to the sun in inches is 1.116 x 10^9 How many fireflies would it take to reach the sun if they were put end to end?
Wittaler [7]

Answer:

THE DISTANCE OF SUB IS 5892480000000IN

1MI=63630 IN

930000000MI=93000000×63360 IN=589248000000IN

X=NUMBER OF FIREFLIES

X=0.4IN=5892480000000IN

X=58924800000000IN×0.4IN

X=147312000000000

3 0
3 years ago
A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n
Ratling [72]

Answer:

a)

k = \dfrac{1}{21}

b) 0.476

c) 0.667    

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

P(y) = ky

a) Property of discrete probability distribution:

\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}

b) at most four forms are required

P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476

c) probability that between two and five forms (inclusive) are required

P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667

8 0
3 years ago
Katie has a collection of nickels, dimes and quarters with a total value of
garik1379 [7]

10d+ 25q+5n= 805

D= n+8

Q= n+ 5



10d+ 25q+5n= 805

10(n+8)+25(n+5)+5n=805

10n+80+25n+125+5n=805

40n+205=805

40n=805-205

40n= 600

N=600/40

N= 15


D= n+8

D= 15+8

D= 23


Q=n+5

Q=15+5

Q=20


So 15 nickels ,23 dimes and 20quarters .


To check

15(0.05)= $0.75

23(0.10)=$2.30

20(0.25)=$5.00


Add it

5.00+2.30+0.75=8.05

7.30+.75=8.05

8.05=8.05

5 0
3 years ago
A bag contains 4 oranges, 3 grapefruits, and 8 tangerines. A piece of fruit is chosen from the bag at random. What is the probab
NARA [144]
Answer is 3/15 which is simplified to 1/5 :)
7 0
3 years ago
Read 2 more answers
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