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SSSSS [86.1K]
2 years ago
6

25. Which word does NOT describe the set of points? (1,5) (2, 2) (3, -1) (4,-4) (5, -7) (6,-10) Decreasing Function Increasing L

inear ​
Mathematics
1 answer:
egoroff_w [7]2 years ago
7 0

Answer:

it would be decreasing

Step-by-step explanation:

because it is a linear increasing function

for 1 it is going up from 1-6

and 2 it is a function because there isn't any multiples of the x values/ inputs that go to one y value/ output.

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There's a width of 8 in., a length of 20 in., and a height of 12 in.
Setler [38]

Answer:

a.

Approximately 24.7\; \rm in.

b.

While there are three diagonals in a box (a rectangular prism,) all three diagonals goes through the same point- the centroid of this box.  

For a maximum-length poster to fit in this box, it would have to be on one of the main diagonals of this box. Hence, any maximum-length poster that fits in this box would go through the centroid of this box.

It's not possible to force more than one posters to go through the same point (i.e., the centroid) in space. Hence, it would not be possible to fit a second maximum-length poster into this box.

This argument does not apply to  21.5\; \rm in posters. These posters are shorter than the diagonal of this box; they could fit inside the box without having to go through a particular point in space.

Step-by-step explanation:

The longest poster that could be fit into this box (a rectangular prism) would be as long as the longest line segment in this box. That line segment would be one of the three diagonals of this box.

Apply the Pythagorean theorem twice to find the length of that diagonal.

Start by finding calculating the diagonal of the base of this box. The base of this box is a rectangle with width 8\; \rm in and length 10\; \rm in. The length of its diagonal would be \sqrt{8^2 + 10^2} inches.

Combine that with the height of this box to find the length of the diagonal of this box.

\begin{aligned}& \sqrt{{\left(\sqrt{8^2 + 10^2}\right)}^2 + 12^2  \\ &= \sqrt{8^2 + 10^2 + 12^2} \\ &\approx 24.7 \end{aligned}.

7 0
3 years ago
The ground temperature at an airport is 10 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g
Paraphin [41]

The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Given that,

  • The ground temperature at the airport is 10 °C.
  • The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.

Based on the above information, the temperature outside should be

The decrease in the temperature should be

= 5.4×5

= 27°C

Now the final temperature is

= 10 - 27

= -17°C

Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Learn more: brainly.com/question/20459283

5 0
2 years ago
How much is 78ml when you turn it to litres<br>​
algol [13]

1000ML = 1 L

78ML ?

78*1/1000 = 0.078 L

5 0
3 years ago
Read 2 more answers
1. Find the perimeter.<br> 13 yd<br> 14 yd<br> 7 yd<br> 18 yd
nikdorinn [45]

Answer:

52 yards

Step-by-step explanation:

Perimeter is all sides added together.

13 + 14 + 7 + 18 = 52

4 0
3 years ago
Read 2 more answers
Solve to find side C please
Alex73 [517]

Answer:

c= 18.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos theta = a/c

cos 57 = 10/c

Multiply each side by c

c cos 57 =10

Divide each side by cos 57

c = 10/cos 57

c=18.36078459

Rounding to the nearest tenth

c= 18.4

6 0
3 years ago
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