This equation shows how the distance Tess runs depends on the number of track practices she attends.
1 answer:
Answer:
Step-by-step explanation:
Let
d ----> distance Tess runs in miles
p ---> the number of track practices she attends
we have
This is a linear equation in slope intercept form
where
The slope or unit rate is
The y-intercept (value of d when the value of p is equal to zero) is
so
For d=11 miles
substitute in the linear equation and solve for p
solve for p
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Answer:
-675
Step-by-step explanation:
The sum can be broken into parts that you know. Here, one of those parts is the sum of numbers 1 to n. That sum is given by n(n+1)/2.
__
Another way to do this is to realize the sequence of numbers is an arithmetic sequence with a first term of 65 and a last term of 67-2·75 = -83.
The sum of an arithmetic sequence is found by multiplying the number of terms by their average value. Their average value is the average of the first and last terms.
The average value of those 75 terms is (65 +(-83))/2 = -9, so their sum is ...
75(-9) = -675