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3 years ago

What's the answerrrrr?

Mathematics

2 answers:

bazaltina [42]3 years ago

8 0

Answer:

A. Positive

Step-by-step explanation:

Im not very good at explaining. I hope I helped :)

SashulF [63]3 years ago

5 0

Answer:

A. Positive

Step-by-step explanation:

Since 48 is way larger than 39, we know that if we subtract 39 from 48, we will still get a positive number.

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HOW do i solve this? <br><br> 7.42 ÷ 1.75

artcher [175]

Answer:

Step-by-step explanation:

You divide 7.42 / 1.75 = the answer is 4.24

7 0

3 years ago

Read 2 more answers

Evaluate the algebraic expression for the given values 6+5(x-6)³ for X=8

Olegator [25]

1086

6+5(x-6)^3
6+5(8-2)^3
6+5(6)^3
6+5(216)
6+1080
=1086

8 0

4 years ago

Use the position equation given below, where s represents the height of the object (in feet), v0 represents the initial velocity

iris [78.8K]

Answer:

(a) 7.5 seconds

(b) The horizontal distance the package travel during its descent is 1737.8 ft

Step-by-step explanation:

(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀

The initial height of the object s₀ = 900 feet

The initial vertical velocity of the object v₀ $_y$ = 0 m/s

The time it takes the package to strike the ground is found as follows;

0 = -16·t² + 0×t + 900

900 = 16·t²

t² = 900/16 = 62.25

t = √62.25 = 7.5 seconds

(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have

158 miles/hour = 231.7126 ft/s

The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place

The horizontal distance the package travel during its descent = 1737.8 ft.

4 0

3 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago

The additive inverse of an element of x of a set is the number, which when added to x gives the answer 0. In the set {-3, -2, -1

Sav [38]

Answer:

Step-by-step explanation:

the additive inverse of - 2 is 2 , since

- 2 + 2 = 0

6 0

2 years ago