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tekilochka [14]
3 years ago
6

Can anyone help me with these questions?

Mathematics
1 answer:
kati45 [8]3 years ago
8 0
1.) The third graph
2.) 35
3.) X=16.1
4.) 56
5.) 77
6.) I`m not sure
7.) I'm not sure

I hope this helps you in your time of need keep up the good work champ :-)
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After John worked at a job for 10 years, his salary doubled. If he started at $x, his salary after 10 years is $_____.
Digiron [165]
If he started at $x, and we need to double it, we take X and multiply it by 2 creating $2X
5 0
3 years ago
−x+10=−5<br><br> Please help and include step by step.
sergey [27]

Step by Step:

Step 1.) Subract 10 from both sides.

Step 2.) Divide each side by one



answer: x=15

3 0
4 years ago
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Can someone please help me with this?
yuradex [85]

Answer:

p = 1.2

Step-by-step explanation:

Bring 3.9 to the other side of the equation.

-10.9p = -13.08

p = 1.2

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3 years ago
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Can someone help me please
Verizon [17]
I have solved it. Answer is B.

Hope it helps!
3 0
4 years ago
Jharana got Rs.1881 interest of certain sum for 2year at 9% compounded yearly.find the sum.​
Lana71 [14]

The principal sum is Rs.10,000

Step-by-step explanation:

The formula of compound interest is:

I=P(1+\frac{r}{n})^{nt}-P where:

  • I is the interest
  • P is the principal investment amount (the initial deposit or loan amount)
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

Jharana got Rs.1881 interest of certain sum for 2 year at 9%

compounded yearly

∵ I = Rs.1881

∵ r = (9/100) = 0.09

∵ n = 1 ⇒ compounded yearly

∵ t = 2 years

Substitute all of these values in the rule above

∴ 1881=P(1+\frac{0.09}{1})^{(1)(2)}-P

∴ 1881 = P(1 + 0.09)² - P

∴ 1881 = P(1.09)² - P

∴ 1881 = 1.1881 P - P

∴ 1881 = 0.1881 P

- Divide both sides by 0.1881

∴ P = 10,000

The principal sum is Rs.10,000

Learn more:

You can learn more about the interest in brainly.com/question/11149751

#LearnwithBrainly

3 0
3 years ago
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