All categories

3 years ago

A person selecting a bank does not need to consider whether the staff is friendly and helpful. True False

2 answers:

8 0

False, A person would not want a bank where they could not depend on the staff and be able to come to them if they were having problems with the bank account

sladkih [1.3K]3 years ago

6 0

The correct answer is False

Explanation:

A bank is one of the most common financial institutions, in this, there are multiple services that include credits, saving bank accounts, and credit/debit cards. Additionally, not all banks offer the same services or have the same conditions, which is why you need to select carefully a bank if you require one or more financial services.

In this process, it is important to consider tariffs or payments, flexibility in services, and also the staff of the bank because they are the people mediating and offering the services and if they are not willing to help you or to do it in a friendly way, you are not going to have support in case you need it, for example in case you need more information or help with an issue. Thus, it is false you do not need to consider whether the staff is friendly and helpful when selecting a bank because this factor affects the support you have from the bank and the general service quality.

You might be interested in

If the volume of a cube is 64 in3, how long is each side?

8_murik_8 [283]

Answer:

Step-by-step explanation:

4*4*4=16*4=64

Please mark as Brainliest! :)

Have a nice day.

5 0

3 years ago

PLZ HELP!!! Use limits to evaluate the integral.

Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

$\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]$

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

$r_i=\dfrac{2i}n$

where $1\le i\le n$ . Each interval has length $\Delta x_i=\frac{2-0}n=\frac2n$ .

At these sampling points, the function takes on values of

$f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}$

We approximate the integral with the Riemann sum:

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3$

Recall that

$\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4$

so that the sum reduces to

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}$

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

$\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}$

Just to check:

$\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28$

4 0

3 years ago

Examine the system of equations. y = 3 2 x − 6, y = −9 2 x + 21 Use substitution to solve the system of equations. What is the v

nadezda [96]

Answer:

Step-by-step explanation:

Given the system of equations y = 3/2 x − 6, y = −9/2 x + 21, since both expressions are functions of y, we will equate both of them to find the variable x;

3/2 x − 6 = −9/2 x + 21,

Cross multiplying;

3(2x+21) = -9(2x-6)

6x+63 = -18x+54

collecting the like terms;

6x+18x = 54-63

24x = -9

x = -9/24

x = -3/8

To get the value of y, we will substitute x = -3/8 into any of the given equation. Using the first equation;

y = 3/2x-6

y = 3/{2(-3/8)-6}

y = 3/{(-3/4-6)}

y = 3/{(-3-24)/4}

y = 3/(-27/4)

y = 3 * -4/27

y = -4/9

Hence, the value of y is -4/9

4 0

3 years ago

Read 2 more answers

Complete the equation of the line through (-10,-7)and-5,-9)<br> Y=

galben [10]

Answer:

$y = - \frac{2}{5} - 11$

4 0

4 years ago

The nature of a graph, which has an even degree and a positive leading coefficient will be

zaharov [31]

The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position

<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>

The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.

Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.

y = f(x) = 2x²+ 4

The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.

Learn more about the graph of a quadratic equation here:

brainly.com/question/9643976

#SPJ1

6 0

2 years ago