The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following
perimeter and area of the trapezium.
<h3>How can the area and perimeter of the trapezium be found?</h3>
The perimeter of a trapezoid is given as follows;
Perimeter = The sum of the lengths of the sides
Which gives;
Perimeter = 6 + 7 + 6.5 + 9.5 = 29
The perimeter of the trapezoid =<u> 29 cm</u>
The area of the trapezoid is given as follows;
Which gives;
The area of the trapezoid = 49.5 cm²
Learn more about the area and perimeter of geometric shapes here:
brainly.com/question/359059
brainly.com/question/11461461
Answer: This one is D.110! ☺️
Answer:
Step-by-step explanation:
cartesian plane :
quadrant 1 : both x and y are positive
quadrant 2 : x is negative, y is positive
quadrant 3 : both x and y are negative
quadrant 4 : x is positive and y is negative
(-2,4)......we have x is negative and y is positive...so we are in quadrant 2
(3,-1)....we have x is positive and y is negative...in quadrant 4
(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x
(1,2)....both are positive....located in quadrant 1
(-3,-5)...both are negative.....quadrant 3
Answer:
C.18(38) +2.5s >/= 750
Step-by-step explanation:
