Answer:
(f-g) (y+c)
Step-by-step explanation:
yf -cg - yg+ cf
Using factor by grouping, y from the first group and c from the second group
yf - yg+ cf -cg
y( f-g) +c(f-g)
Factor out (f-g)
(f-g) (y+c)
So, the first thing is that the group requires flashlight to cross the bridge. It also means that each time one person must return to bring back the flashlight.
Chris and Tracy cross the bridge in 2 minutes. ( The maximum time required by both of them would be 2 minutes)
Then Chris would return with flashlight in 1 minute.
Ashley and Jalen then cross the bridge in 10 minutes.
Now, Tracy will return with flash light in 2 minutes.
Then, Chris and Tracy will cross the bridge in 2 minutes.
<u>Total</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>=</u><u>></u> 2+1+10+2+2 <u>=</u><u>></u> 17 minutes.
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Answer:
39 mph
26 mph
Step-by-step explanation:
distance = rate * time
20 minutes:
13 miles = rate * 20 minutes
rate = (13 miles)/(20 minutes) * (60 minutes)/(hour)
rate = 39 mph
30 minutes:
13 miles = rate * 30 minutes
rate = (13 miles)/(30 minutes) * (60 minutes)/(hour)
rate = 26 mph
Answer: 4 hours
Step-by-step explanation:
10+6=16
16+6=22
22+6=28
28+6=34
The summand (R?) is missing, but we can always come up with another one.
Divide the interval [0, 1] into 
subintervals of equal length 
:
![[0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right]](https://tex.z-dn.net/?f=%5B0%2C1%5D%3D%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%5Ccup%5Ccdots%5Ccup%5Cleft%5B1-%5Cdfrac1n%2C1%5Cright%5D)
Let's consider a left-endpoint sum, so that we take values of 
where 
is given by the sequence
with 
. Then the definite integral is equal to the Riemann sum
