The solution to system is x = 0 and y = -1
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-8x + 2y = -2 ----------- eqn 1
4x + 4y = -4 ---------- eqn 2
We have to solve the system of equations
We can solve the equations by elimination method
<em><u>Multiply eqn 2 by 2</u></em>
8x + 8y = -8 ------ eqn 3
<em><u>Add eqn 1 and eqn 3</u></em>
-8x + 2y = -2
8x + 8y = -8
( + ) ---------------
0x + 2y + 8y = -2 - 8
10y = -10
Divide both sides by 10
y = -1
<em><u>Substitute y = -1 in eqn 1</u></em>
-8x + 2(-1) = -2
-8x - 2 = -2
-8x = -2 + 2
x = 0
Thus the solution to system is x = 0 and y = -1
Answer:
I'm pretty sure it's 4 sorry if I'm not right I'm not the best at this stuff either
Angle E is from A to E
see, the 0 is on the right
from 0 to 120, look at inner arc
answer si 120 degres
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