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stepan [7]
3 years ago
11

Friday​ night, a pizza parlor sold

Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0
The total is. Friday 573
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Laura's job is 4 1/2 miles away. If she starts walking to her job at 9:00 a.m. and is scheduled to start working at 11:00 a.m.,
irina [24]

Answer:

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Distance from Laura's home to her job = 4 1/2 miles

Time when Laura starts to walk to her job : 9:00 a.m.

Time when Laura is scheduled to start working : 11:00 a.m.

2.  Will she arrive at her job on time?

Time Laura has to complete the distance from her home to her job = 2 hours (11 -9)

Speed that Laura need to walk to arrive to her job on time = Distance from Laura's home to her job/Time Laura has to complete the distance from her home to her job

Speed that Laura need to walk to arrive to her job on time = 4 1/2 miles/2 hours = (4 1/2)/2 = (9/2)/2 = 9/2 * 1/2 = 9/4 = 2 1/4

Speed that Laura need to walk to arrive to her job on time = 2 1/4 miles per hour.

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

7 0
2 years ago
5y^2+5−4−4y^2+5y^2−4x^3 −1
vredina [299]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

Collect like terms

⇒\sf{ 4 {x}^{3}  + 5 {y}^{2}  - 4 {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  +  {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 5 - 4 - 1}

Calculate

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

Hope I helped!

Best regards! :D

6 0
2 years ago
A man has 1/2 of a kilogram of rice. He shares it equally amongst 6 people. How many kilograms does each person get? Input your
Degger [83]

Answer:

1/12

Step-by-step explanation:

5 0
3 years ago
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You want path 1 to be a continuous distance of 1.5 km from the center of the habitat 1) path one represents what mathematical ob
oksian1 [2.3K]
If we consider the center of the habitat to be a point - then a circle with a radius of 1.5 km <u /><u />would satisfy the problem.

The path would go around the point (habitiat) and would always be 1.5 km from that point.
3 0
2 years ago
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What are the like terms in this exspression 9a-3b + 4ab
vova2212 [387]

Answer:

none of these terms are like terms

7 0
2 years ago
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