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3 years ago

26 Points!!! Select True or False for each equation.

Mathematics

2 answers:

statuscvo [17]3 years ago

8 0

Answer:

1) True

2) False

Step-by-step explanation:

- 6/2 = -3

ArbitrLikvidat [17]3 years ago

4 0

Answer:

The first one is true, meanwhile the second is false!

Step-by-step explanation:

The first one both simplify to -3.

The second one, -6/-2 ( fraction ) simplifies to positive 3 because dividing or multiplying by 2 negative numbers cancels out the negative sign.

Hope it helps!

You might be interested in

All of the expressions that have the same value as LaTeX: 892\div8892 ÷ 8. Group of answer choices LaTeX: 8920\div808920 ÷ 80 La

algol13

Answer:

$(a)$ $8920\div80$

$(e)$ $0.892\div0.008$

Step-by-step explanation:

Given

$892\div8$

Required

Select equivalent expression

$8920\div80$

$894\div10$

$89.2\div0.08$

$8.92\div0.8$

$0.892\div0.008$

Start by solving the given expression (using a calculator)

$892\div8$ $= 111.5$

Then we solve the given options (using a calculator)

$(a)$ $8920\div80$

$8920\div80$ $= 111.5$

$(b)$ $894\div10$

$894\div10$ $= 89.4$

$(c)$ $89.2\div0.08$

$89.2\div0.08$ $= 1115$

$(d)$ $8.92\div0.8$

$8.92\div0.8$ $= 11.15$

$(e)$ $0.892\div0.008$

$0.892\div0.008$ $= 111.5$

The equivalent expressions are (a) and (e)

5 0

2 years ago

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago

Ebony walked at a rate of 3 1/2 miles per hour for 1 1/3 hours. how far did she walk.

Pachacha [2.7K]

About 4.65 miles. Multiply 3 1/2 (3.5) by 1 1/3 (1.33) and thats how you get the answer

7 0

2 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

Find the volume of the cylinder. Use 3.14 for T.<br><br> height of 5m radius of 15m

Lilit [14]

Answer:

739.47

Step-by-step explanation:

height - h, radius -r

V=hπ²r=5×3.14²×15=739.47

5 0

2 years ago

Read 2 more answers