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spayn [35]
3 years ago
5

What he the value of n? 3n+16=7n

Mathematics
2 answers:
balandron [24]3 years ago
7 0

Answer: 4

Step-by-step explanation:

4n = -16 / 4

4

PICK me for BRAINLIEST PLEASE

Vlad [161]3 years ago
5 0

Answer:

The answer is 4

Step-by-step explanation:

3n+16=7n

collect like terms

-4n=-16

divide by -4

n=4

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Which point is a reflection of T(-6.5, 1) across the x-axis and the y-axis?
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Write an equation that represents the line. use exact numbers.​
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Step-by-step explanation:

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3 0
2 years ago
7.4 Practice
pickupchik [31]

The simulation of the medicine and the bowler hat are illustrations of probability

  • The probability that the medicine is effective on at least two is 0.767
  • The probability that the medicine is effective on none is 0
  • The probability that the bowler hits a headpin 4 out of 5 times is 0.3281

<h3>The probability that the medicine is effective on at least two</h3>

From the question,

  • Numbers 1 to 7 represents the medicine being effective
  • 0, 8 and 9 represents the medicine not being effective

From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two

So, the probability is:

p = 23/30

p = 0.767

Hence, the probability that the medicine is effective on at least two is 0.767

<h3>The probability that the medicine is effective on none</h3>

From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none

So, the probability is:

p = 0/30

p = 0

Hence, the probability that the medicine is effective on none is 0

<h3>The probability a bowler hits a headpin</h3>

The probability of hitting a headpin is:

p = 90%

The probability a bowler hits a headpin 4 out of 5 times is:

P(x) = nCx * p^x * (1 - p)^(n - x)

So, we have:

P(4) = 5C4 * (90%)^4 * (1 - 90%)^1

P(4) = 0.3281

Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281

Read more about probabilities at:

brainly.com/question/25870256

8 0
2 years ago
what is the probability of randomly selecting a score between 1 and 2 standard deviations below the mean?
velikii [3]

Answer:

0.13591.

Step-by-step explanation:

We re asked to find the probability of randomly selecting a score between 1 and 2 standard deviations below the mean.

We know that z-score tells us that a data point is how many standard deviation above or below mean.

To solve our given problem, we need to find area between z-score of -2 and -1 that is P(-2.

We will use formula P(a to solve our given problem.

P(-2

Using normal distribution table, we will get:

P(-2

P(-2

Therefore, the probability of randomly selecting a score between 1 and 2 standard deviations below the mean would be 0.13591.

8 0
3 years ago
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