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docker41 [41]
3 years ago
12

Claire bought 180 candies and 140 pens for goody bags for her birthday. What is the largest number of goody bags that Claire can

make so that each goody bag has the same number of candies and the same number of pens?
Mathematics
2 answers:
Kruka [31]3 years ago
6 0
Wouldn't it be 140 bags with one of each in it; unless you need to use all the candies?
Kitty [74]3 years ago
6 0

Answer: 20

Step-by-step explanation:

Given : Claire bought 180 candies and 140 pens for goody bags for her birthday.

To find : The largest number of goody bags that Claire can make so that each goody bag has the same number of candies and the same number of pens ( such that no pens or candies left).

So we find the GCF ( Greatest common factor ) or Number of candies and Number of pens.

i.e. we need to find GCF of 180 and 140 .

Prime factorization of 180 = 2\times2\times3\times3\times5

Prime factorization of 140 =2\times2\times7\times5

The greatest common factor of 180 & 140 = 2\times2\times5=20

∴ Claire can make 20 goody bags so that each goody bag has the same number of candies and the same number of pens.

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its 76 degrees fahrenheit at the 6000-foot level of a mountain, and 49 degrees Fahrenheit at the 12000-foot level of the mountai
brilliants [131]

T = \frac{-9}{2}x + 103 is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.

<em><u>Solution:</u></em>

The linear equation in slope intercept form is given as:

T = cx + k ------ (i)

Where "t" is the temperature at an elevation x

And x is in thousands of feet

<em><u>Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain</u></em>

Given, when c = 6 thousand ft and T = 76^{\circ} fahrenheit

This implies,

From (i)

76 = c(6) + k

76 = 6c + k

⇒ k = 76 - 6c  ----- (ii)

<em><u>Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain</u></em>

Given, when c = 12 thousand ft and T = 49^{\circ} fahrenheit

This implies,

From (i)

49 = c(12) + k

49 = 12c + k

Substitute (ii) in above equation

49 = 12c + (76 - 6c)

49 = 12c + 76 - 6c

49 - 76 = 6c

6c = -27

c = \frac{-9}{2}

Substituting the value of c in (ii) we get

k = 76 - 6( \frac{-9}{2})\\\\k = 76 + 27 = 103

Substituting the value of c and k in (i)

T = \frac{-9}{2}x + 103

Where "x" is in thousands of feet

Thus the required linear equation is found

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(5, -12); m
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