Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
The coordinates of point S would be (10,6), so the distance from point T to point S would be 13. :)
both (0,350) and (250,700) fall in the shaded are
and check:
350 *3 = 1050, which is more than 1000 and more than double the amount of hotdogs ( 0)
700 *3 = 2100, so over 1000 and more than double the amount of hotdogs(250*2=500)
so those 2 are correct
Answer:
B) 4
Step-by-step explanation:
Tan is opposite/adjacent. That means that 3 is the opposite side while 4 is the adjacent side.
Answer:
x= 5/2 or 1/2
Step-by-step explanation:
absolute value always gives us positive
if |u| = 2, u can be -2 or 2
2x-3 = 2
2x = 5
x = 5/2
2x-3 = -2
2x = 1
x= 1/2
in general, set the stuff inside the absolute value to equal both positive and negative of the equivalent value